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lianna [129]
3 years ago
10

What is the electron configuration of an element with atomic number 15?

Chemistry
1 answer:
Ghella [55]3 years ago
4 0
1s to the second power, 2s to the second power, 2p to the 6th power, 3s to the second power and 3p to the third power.
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Determine whether or not baco3 will be more soluble in acidic solution than in pure water.
Volgvan
Barium carbonate (BaCO₃) <span>will be more soluble in acidic solution than in pure water, because Ksp (solubility constant) in water for this salt is very low.
In acid (for example hydrochloric acid) barium carbonate dissolves more because it forms weak electrolyte carbonic acid:
BaCO</span>₃(s) + 2HCl(aq) → BaCl₂(aq) + H₂CO₃(aq).
4 0
3 years ago
Consider the hydrate FeSO4 • 7H2O.
DochEvi [55]
The molar mass of the hydrate is 278.06
The molar mass of the anhydrous salt is 151.92
The molar mass of water in the hydrate is 126.14
7 0
3 years ago
Read 2 more answers
As a change of state takes place, heat and temperature
Alexeev081 [22]

Answer:

c. stays the same, changes

Explanation:

temperature and heat go hand in hand, however while the change of state occurs, the temperature remains the same while the heat increases since the heat input is constant.

5 0
3 years ago
A student measures the length and mass of an object records the link is 45.2 cm convert distance measurement to the correct SI b
horrorfan [7]

In science, physical quantities like length, weights etc are measured in units of metric or International System of units.

Some importance units are as follows:

1. Meter (m) for length.

2. Liter (L) for volume.

3. Gram (g) and kilogram (kg) for mass.

4. Degree Celsius (oC) for temperature.

5. Second for (s) time.

Given that the length of an object = 45.2 cm

SI unit of length is m

100 cm = 1.0 m

Therefore  

45.2 cm * 1 .0 m/100 cm

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4 0
3 years ago
An aqueous solution has a hydrogen ion contamination of 1.15x10^-2M (1)What is the hydroxide ion concentration in this solution?
Misha Larkins [42]

Answer:

See explanation

Explanation:

We know that

pH = - log [H^+]

but [H^+] = 1.15x10^-2M

Hence;

pH =  - log(1.15x10^-2)

pH = 1.94

And;

pH + pOH = 14

pOH = 14-pH

pOH = 14 - 1.94

pOH = 12.06

Since;

pOH = - log [OH^-]

hence;

[OH^-] = Antilog (-pOH)

[OH^-] = Antilog (12.06)

[OH^-] = 8.7 * 10^-13 M

8 0
2 years ago
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