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leonid [27]
3 years ago
9

Please help me out! Fr

Chemistry
1 answer:
il63 [147K]3 years ago
6 0

<em>please</em><em> </em><em>wait </em><em>I </em><em>am </em><em>answering</em>

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2 significant figures

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\boxed{\text{2408 min}}

Explanation:

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\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

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t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

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