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Ilia_Sergeevich [38]
3 years ago
15

Periodic motion can BEST be defined as motion

Physics
1 answer:
koban [17]3 years ago
8 0

Answer:

C

Explanation:

repeated in intervals of time

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Which vector has an x-component with a length of 4?
zepelin [54]

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

7 0
3 years ago
You kick a soccer ball across a field the ball travels across the field and slowly comes to a stop. Since the ball slowly comes
marysya [2.9K]

Answer:

It slowly decreases and the friction acting on it slowing it down becomes the bigger net force, if that makes sense :)

Explanation:

6 0
3 years ago
Please help me with this​
AfilCa [17]

Answer:

20 N exerts no torque about the pivot.

14 N exerts a counterclockwise torque of 14 * .3 = .42 N-m

6  exerts a clockwise torque of 6 * .7 = .42 N-m

The meter stick will not turn because there is no net torque on the meter stick.

3 0
2 years ago
A satellite orbiting Earth has a tangential velocity of 5000 m/s. Earth’s mass is 6 × 1024 kg and its radius is 6.4 × 106 m.
Aloiza [94]
When a satellite is moving around the Earth's orbit, two equal forces are acting on it. The centripetal and the centrifugal force. The centripetal force is the force that attracts the object toward the center of the axis of rotation. The opposite force is the centrifugal force. It draws the object away from the center. When these forces are equal, the satellite uniformly rotates along the orbit.

Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration

\frac{ M_{E}*G }{  ( r_{E} )^{2}  } =ω^2r

where

M_{E} = mass of earth
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>r_{E} = radius of earth
ω = angular velocity
<span>r = radius of orbit

To convert to angular velocity:

</span>Tangential velocity = rω
ω = 5000/r

Then,

\frac{ (6 \ x \  10^{24}) *(6.6742 \ x \ 10^{-11} ) }{ ( 6.4 \ x \  10^{6})^{2} }= ( \frac{5000}{r} )^{2} r

r = 2557110.465 m

Therefore, the distance of the centers of the earth and the satellite is 2.6 x 10^6 m.
<span>
</span>
4 0
3 years ago
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Witch of the following questoons would you expect to see on an interest inventory
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Answer: Do you like science experiments ? 1)

Would You enjoy reading a fashion magazine? 2)

Explanation:

3 0
3 years ago
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