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Ilia_Sergeevich [38]

2 years ago

15

Periodic motion can BEST be defined as motion

1 answer:

koban [17]2 years ago

8 0

Answer:

C

Explanation:

repeated in intervals of time

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What subatomic particle acts like a mini-magnet?

Semenov [28]

The subatomic particles that acts like a mini-magnet is electron. Electrons are negatively charged sub atomic particles in an atom. The electron spin is a property of an electron that makes it behave like it's spinning; a spinning electron produces a magnetic field that makes it behave like a tiny magnet in an atom.

5 0

2 years ago

23 grams of sodium reacted with 35.5 grams of chlorine. Calculate the mass of the sodium chloride compound formed

xxTIMURxx [149]

According to law of conservation of mass within a reaction,
The mass of the compound formed is (23+35.5) grams means 58.5 grams of sodium chloride[NaCl] will be formed.

3 0

3 years ago

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Having a good range of motion is super important because that is what allows you to ________________.

kotykmax [81]

A is the correct answer I think

6 0

2 years ago

What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?

Neko [114]

Answer:

Mechanical advantage = 4

Explanation:

Given the following data;

Distance of effort, de = 8m

Distance of ramp, dr = 2m

To find the mechanical advantage;

Mechanical advantage = de/dr

Substituting into the equation, we have;

Mechanical advantage = 8/2

Mechanical advantage = 4

5 0

2 years ago

The block in the diagram below is AT REST. However, the tension in the cable is not the only thing holding the block back. Stati

Vedmedyk [2.9K]

Answer:

The tension in the rope is 229.37 N.

Explanation:

Given:

Mass of the block is, $m=33.2\ kg$

Coefficient of static friction is, $\mu = 0.214$

Angle of inclination is, $\theta = 31.5$ °

Draw a free body diagram of the block.

From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.

Forces acting are $mg\cos \theta$ and normal $N$ . Now, there is no motion in the direction perpendicular to the inclined plane. So,

$N=mg\cos \theta\\N=(33.2)(9.8)\cos (31.5)\\N=277.415\ N$

Consider the direction along the inclined plane.

The forces acting along the plane are $mg\sin \theta$ and frictional force, $f$ , down the plane and tension, $T$ , up the plane.

Now, as the block is at rest, so net force along the plane is also zero.

$T=mg\sin \theta+f\\T=mg\sin \theta +\mu N\\T= (33.2)(9.8)(\sin (31.5)+(0.214\times 277.415)\\T= 170+59.37\\T=229.37\ N$

Therefore, the tension in the rope is 229.37 N.

3 0

2 years ago