Answer:
5.4kgm/s towards the hitter.
Explanation:
Given parameters:
Mass = 0.12kg
Velocity = 45m/s
Unknown:
Momentum of the baseball = ?
Solution:
To solve this problem, we must understand that the momentum of a body is the quantity of motion it possesses.
Momentum = mass x velocity
Now insert the parameters and solve;
Momentum = 0.12 x 45 = 5.4kgm/s towards the hitter.
Answer:
Explanation:
Remark
Anybody who has dealt with Christmas Tree lights knows what can be done. You must take a bulb you know to be good and try each bulb in turn until the whole string lights up. If two bulbs are dead, give up and go buy another string. Two bulbs create a lot of combinations.
The circuit is a series circuit.
okay u need to use the equation m=Fnet/a. Fnet=540N a=7.74m/s^2 m=540N/7.74m/s^2=69.77kg
Answer:
3.88m/s
Explanation:
Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and 2 are the initial velocities
v is the final velocity
Given
m1 = 64kg
u1 = 4.2m/s
m2 = 25kg
u2 = 3.2m/s
Required
Final velocity v
Substitute the given values into the formula
64(4.2)+25(3.2) = (65+25)v
268.8+80 = 90v
348.8 = 90v
v = 348.8/90
v = 3.88m/s
Hence the velocity of the kayak after the swimmer jumps off is 3.88m/s
Answer:
Magnetic dipole moment is 0.0683 J/T.
Explanation:
It is given that,
Length of the rod, l = 7.3 cm = 0.073 m
Diameter of the cylinder, d = 1.5 cm = 0.015 m
Magnetization, ![M=5.3\times 10^3\ A/m](https://tex.z-dn.net/?f=M%3D5.3%5Ctimes%2010%5E3%5C%20A%2Fm)
The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :
![M=\dfrac{\mu}{V}](https://tex.z-dn.net/?f=M%3D%5Cdfrac%7B%5Cmu%7D%7BV%7D)
![\mu=M\times \pi r^2\times l](https://tex.z-dn.net/?f=%5Cmu%3DM%5Ctimes%20%5Cpi%20r%5E2%5Ctimes%20l)
Where
r is the radius of rod, r = 0.0075 m
![\mu=5.3\times 10^3\ A/m\times \pi (0.0075)^2\times 0.073\ m](https://tex.z-dn.net/?f=%5Cmu%3D5.3%5Ctimes%2010%5E3%5C%20A%2Fm%5Ctimes%20%5Cpi%20%280.0075%29%5E2%5Ctimes%200.073%5C%20m)
![\mu=0.0683\ J/T](https://tex.z-dn.net/?f=%5Cmu%3D0.0683%5C%20J%2FT)
So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.