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3 years ago

8

The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act

ivity D. cost of an activity

2 answers:

marta [7]3 years ago

8 0

Answer:

B.

Explanation:

According to CDC, if you’re doing moderate-intensity activity, you can talk but not sing during the activity.

Licemer1 [7]3 years ago

4 0

It is b for your answer

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Which explains the information needed to calculate speed and velocity?

goblinko [34]

The second statement is the correct choice. Don't make me type it out.

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3 years ago

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How are pupae, larvae, and nymphs similar? *Answer Fast!*

Goshia [24]

Answer:

They are all a cycle!

Explanation:

They just are all cycles.

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2 years ago

A cube-shaped piece of copper has sides of 4cm each and it's density is

iris [78.8K]

Answer:

$64 cm^3$

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

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$V=(4\ cm)^3=64\ cm^3$

Surprisingly, no other magnitude is required, thus the answer is:

$\mathbf{64 cm^3}$

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2 years ago

An electric heater is operated by applying a potential difference of 78.0 V across a nichrome wire of total resistance 7.00 Ω. a

aleksley [76]

PART A)

Here we know that

potential difference across the wire is

$V = 78 volts$

resistance of wire is

$R = 7 ohm$

now by ohm's law

$V = iR$

$78 = i(7 ohm)$

$i = 11.14 A$

Part b)

Power rating is defined as rate of electrical energy

it is defined as

$P = iV$

now we have

$P = 11.14 ( 78)$

$P = 869.1 Watt$

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2 years ago

Una flecha tiene una rapidez de lanzamiento inicial de 18 m/s. Si debe dar en un blanco a 31 m de distancia, que está a la misma

maks197457 [2]

Answer:

34.8 and 55.2º

Explanation:

This is a projectile launching exercise, as we are told that the range of the arrow must be equal to its range and = 31 m let's use the equation

The scope equation is

R = v₀² sin 2θ /g

sin 2 θ = R g / v₀²

sin 2 θ = 31 9.8 / 18²

2 θ = sin⁻¹ 0.93765

θ = 34.8º

At the launch of projectiles we have two complementary angles with the same range in this case 34.8 and (90-34.8) = 55.2º

4 0

3 years ago