The specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.
<h3>Conseervation of energy</h3>The heat capacity of the calirometer is determined by applying the principle of conservation of energy.
Heat lost by the hot water = Heat gained by the calirometer
where;
- M is mass
mass = density x volume = ρV
Density of water = 1 g/ml
Mass of hot water = 1 x (50) = 50 g
Mass of water in calorimeter = 1 x (60) = 60 g
<h3>Equilibrium temperature</h3>Thus, the specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.
The complete question is below
When using a different calorimeter, and mixing 50 ml of hot water at
65 degrees C with 60 ml of water in the calorimeter at 25 degrees C, the temperature of the calorimeter increased by 5.5 degrees C.
a. Calculate the heat capacity of this calorimeter?
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