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hichkok12 [17]
3 years ago
6

What is the Bond Type and Molecular polarity of PCl3?

Chemistry
2 answers:
Aleks [24]3 years ago
5 0

Answer:

It is covalent bonding. The electrons are shared between the phosphorus and the chlorines.

covalent bonding is when electrons are shared between two elements.

Explanation:

DedPeter [7]3 years ago
4 0
It is covalent bonding. The electrons are shared between the phosphorus and the chlorines.

covalent bonding is when electrons are shared between two elements.

molecular polarity is a little bit complicated, but I will try to explain ;)
PCl3 is an alternation on tetrahedral molecules.
It means that P has one lone pair of electrons. This pair of electrons are only attracted to the P nuclei and thus a greater freedom of motion.
This means that their orbital is bigger and this pushes the 3 Cl atoms closer together.
The angle between each Cl now is 107 and the angle between Cls and P is greater than 107.
Now, due to this shape, and also electronegativity (Cl is more electronegative than P meaning that it tends to hog the electrons they share closer to itself), PCl3 is polar. Electrons that are shared tend to flow closer towards the Cl than the P side.
Therefore, on the Cl side of the molecule it's, more negative. On the P side, it's more positive.
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A sample of an unknown liquid has a volume of 24.0 mL and a mass of 6 g. What is its density? Show your work or explain how you
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3 years ago
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Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

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Mass of the container = 0.325 kg

Mass of water = 1.75kg

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The specific heat of aluminium = 0.22 Cal/kg°C

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Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

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⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

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ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

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Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

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