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Katyanochek1 [597]

3 years ago

14

Can someone help me out with this please

1 answer:

Dmitriy789 [7]3 years ago

5 0

Answer:

$molar \: mass \: of \: copper(ii)nitrate = 64 + (14 + 48) \times 3 \\ = 250 \: g \\ 64 \: g \: of \: copper \: produces \: 250 \: g \: of \: copper \: nitrate \\ 10.36 \: g \: of \: copper \: will \: produce \: ( \frac{10.36 \times 250}{64} ) \: g \\ = 40.7 \: g$

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