Answer:
The emf of the electrochemical cell has been calculated to be <u>3.364.</u>
in order to calculate the emf we need to apply Nernst equation.
The emf has been the potential of the cell in the reaction with the change in the electrons in the reaction. The emf of the cell has been given by the Nernst equation as -
emf= E⁰ cell - 0.059/n. log 1/concentration
Computation for the emf of the cell
The given cell has the number of electrons transfer, n= 2
The concentration of Pb2= 0.57 M
The concentration of H= 0.090 M
The cell potential of the reaction has been= -0.126
Substituting the values for the emf of the cell:
emf= -0.126- 0.059/2 * log 1/ [0.57]x [0.090] ²
emf= 1.555* 2.337
emf=3.634 v
The emf of the electrochemical cell has been calculated to be 3.634 v.
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