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Vika [28.1K]
3 years ago
15

Development occurs:

Physics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

D

Explanation:

:(

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Think of a body which is at rest but not in equilibrium
REY [17]

Answer:

I think the sun is the right answer

8 0
3 years ago
A 0.5 kg turntable with a radius of 15 cm is rotating 78 times per minute.
alexandr1967 [171]

Answer:

c

Explanation:

8 0
3 years ago
A 135 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 63.
Nutka1998 [239]

Answer:

the  moment of inertia is 380.14 kg-m^2

Explanation:

The computation of the moment of inertia is as follows:

The net moment of inertia is

= MR^2 ÷ 2 + m_p d_p^2 + m_d d_d^2

= 135 × 1.95^2 ÷2 + 63.7 ×  1.05^2 + 30.1 × 1.33^2

= 380.14 kg-m^2

hence, the  moment of inertia is 380.14 kg-m^2

We simply applied the above formula so that the correct value could come

And, the same is to be considered

8 0
3 years ago
The atmosphere of Mercury and Mars are very thin. What effect does the thin atmosphere have on the temperature on the surface of
KengaRu [80]

Answer:

Very hot during the day and very cold at night.

Explanation:

Due to the thin atmosphere, they have very hot climate during the day time and very cold climate at night. This happens because they contain very low amounts of greenhouse gases. These gases retain the heat at night. The atmosphere also prevents excessive light and UV rays from entering. The thin  atmosphere leads to many asteroids and comets hitting the surface of the planet. On earth, these asteroids usually, burn up in the mesosphere layer of the atmosphere. These asteroid collisions cause massive fires. This in turn,  causes the temperature to increase during the day. During the night time, massive fires cannot burn due to the low temperature because of the lack of greenhouse gases.

3 0
3 years ago
A 0.600-mm diameter wire stretches 0.500% of its length when it is stretched with a tension of 20.0 N. What is the Young's modul
n200080 [17]

Answer:

(B) 1.41 x 10^{10} N/m^{2}

Explanation:

diameter of wire (d) = 0.6 mm = 0.0006 m

radius of wire (r) = 0.0006/2 = 0.0003 m

tension (force F) = 20 N

percentage strain = 0.5 %

what is the Young's modulus?

Young's modulus = \frac{stress}{strain}

where

  • stress = force/area

        stress = \frac{force}{πr^{2}}

        stress = \frac{20}{πx0.0003^{2}}

        stress =70735530.3 N/m^{2}

  • strain = percentage strain ÷ 100

        strain = 0.5 ÷ 100 = 0.005

therefore Young's modulus = \frac{stress}{strain} =\frac{70735530.3}{0.005} = 1.41 x 10^{10} N/m^{2}

3 0
3 years ago
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