Ω₀ = the initial angular velocity (from rest)
t = 0.9 s, time for a revolution
θ = 2π rad, the angular distance traveled
Let
α = the angular acceleration
ω = the final angular velocity
The angular rotation obeys the equation
(1/2)*(α rad/s²)*(0.9 s)² = (2π rad)
α = 15.514 rad/s²
The final angular velocity is
ω = (15.514 rad/s²)*(0.9 s) = 13.963 rad/s
If the thrower's arm is r meters long, the tangential velocity of release will be
v = 13.963r m/s
Answer: 13.963 rad/s
Answer:![81.57\mu V](https://tex.z-dn.net/?f=81.57%5Cmu%20V)
Explanation:
Given
radius of circular region r=1.50 mm
![A=\pi r^2=7.069\times 10^{-6}\ m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D7.069%5Ctimes%2010%5E%7B-6%7D%5C%20m%5E2)
Magnetic Field ![B=1.50\ T](https://tex.z-dn.net/?f=B%3D1.50%5C%20T)
time t=130 ms
Flux is given by
![\phi =B\cdot A](https://tex.z-dn.net/?f=%5Cphi%20%3DB%5Ccdot%20A)
change in Flux ![d\phi =(B_f-B_i)A](https://tex.z-dn.net/?f=d%5Cphi%20%3D%28B_f-B_i%29A)
Emf induced is ![e=\frac{\mathrm{d} \phi}{\mathrm{d} t}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%5Cphi%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
![e=\frac{(1.5)\cdot 7.069\times 10^{-6}}{130\times 10^{-3}}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7B%281.5%29%5Ccdot%207.069%5Ctimes%2010%5E%7B-6%7D%7D%7B130%5Ctimes%2010%5E%7B-3%7D%7D)
![e=81.57 \mu V](https://tex.z-dn.net/?f=e%3D81.57%20%5Cmu%20V)
According to Hooke's Law formula. The force is proportional to the displacement of the spring. I believe
You will be left with 106 kids
<h3>Meaning of word problem</h3>
A word problem can be defined as a mathematical problem that is written in word or written in a sentence format.
In a word problem, the student is expected to decode the sentence into a mathematical expression before solving
In conclusion, You will be left with 106 kids
Learn more about word problems: brainly.com/question/13818690
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