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Reika [66]
3 years ago
14

In MCG, the coil is wound by wire making 50 turns. If the radial magnetic field has a density of 0.2 Tesla, what would be the ma

gnitude of magnetic force if a current of 5A is passed through the hair springs.​
Physics
2 answers:
ElenaW [278]3 years ago
8 0
  • Magnetic field density=B=0.2T
  • Current=I=5A
  • Length=l=1m

Magnetic Force be F

\\ \bull\tt\longmapsto F=BI\ell

\\ \bull\tt\longmapsto F=0.2(5)(1)

\\ \bull\tt\longmapsto F=1N

vekshin13 years ago
6 0

Answer:

From the formular of magnetic force:

F= BIl

• F » magnetic force, B » magnetic flux density, I » current, l » length [ assume l = 1 m ]

F = (0.2 \times 5 \times 1) \\  = 1 \: newton

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LuckyWell [14K]

<u>Answer</u>

The acceleration is

a=-2.5ms^{-2} to the nearest tenth

<u>Explanation</u>

Since the car was travelling at 37ms^{-1} before it starts to decelerate, the initial velocity is

u=37ms^{-1}.

The final velocity is v=0ms^{-1}, because the car came to a stop.

The time taken is t=15s.

Using the Newton's equation of linear motion,

v=u +at, we find the acceleration by substituting the known values.


This implies that,

0=37 +a(15)

This gives us,

0-37=15a


\Rightarrow -37=15a


We divide both sides by 15 to get,

a=-\frac{37}{15}ms^{-2}

or

a=-2.46667ms^{-2}




6 0
3 years ago
A ball is thrown 20.0 m/s at an angle of 40.0° with the horizontal. Assume the ball is thrown at ground level.
TEA [102]
The ball's horizontal component of velocity (ie it's horizontal speed) is 20 cos 40degrees. Without knowing the distance of the ball to the wall it's difficult to go further ...
8 0
3 years ago
Determine the acceleration of a pendulum bob as it passes through an angle of 15 degrees to the right of the equilibrium point.
BigorU [14]

Answer:

Explanation:

Since energy is conserved:

2

mu  

2

 

​

=  

2

mv  

2

 

​

+mgh

⇒u  

2

=v  

2

+2gh

⇒(3)  

2

=v  

2

+2(9.8)(0.5−0.5cos60)

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7 0
3 years ago
A 50 W light bulb is plugged into a standard
wolverine [178]

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

energy =50x31x24=37200

=37.2kwh

1kwh =3.39

37.2kwh=3.39x37.2=126.108cent

=$1.26

8 0
2 years ago
The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The
12345 [234]

Answer:

The electric field is 8.75 \times 10^{6}~v~m^{-1} and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field (\vec{E}) is given by \vec{E} = - \nabla V, 'V' being the potential.

In 1-D, it can be written as

E=\dfrac{V}{d}

where 'd' is the separation of space in between the potential difference is created.

Given, V = 0.070~V~ and the thickness of the cell membrane is d = 8.0 \times 10^{-9}~m.

Therefore the created electric field through the cell membrane is

E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}

5 0
3 years ago
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