Question

In MCG, the coil is wound by wire making 50 turns. If the radial magnetic field has a density of 0.2 Tesla, what would be the magnitude of magnetic force if a current of 5A is passed through the hair springs.​

Answer 1

• Magnetic field density=B=0.2T
• Current=I=5A
• Length=l=1m

Magnetic Force be F

$\\ \bull\tt\longmapsto F=BI\ell$

$\\ \bull\tt\longmapsto F=0.2(5)(1)$

$\\ \bull\tt\longmapsto F=1N$

Answer 2

Answer:

From the formular of magnetic force:

$F= BIl$

• F » magnetic force, B » magnetic flux density, I » current, l » length [ assume l = 1 m ]

$F = (0.2 \times 5 \times 1) \\ = 1 \: newton$