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3 years ago

14

In MCG, the coil is wound by wire making 50 turns. If the radial magnetic field has a density of 0.2 Tesla, what would be the ma

gnitude of magnetic force if a current of 5A is passed through the hair springs.

2 answers:

ElenaW [278]3 years ago

8 0

Magnetic field density=B=0.2T
Current=I=5A
Length=l=1m

Magnetic Force be F

$\\ \bull\tt\longmapsto F=BI\ell$

$\\ \bull\tt\longmapsto F=0.2(5)(1)$

$\\ \bull\tt\longmapsto F=1N$

vekshin13 years ago

6 0

Answer:

From the formular of magnetic force:

$F= BIl$

• F » magnetic force, B » magnetic flux density, I » current, l » length [ assume l = 1 m ]

$F = (0.2 \times 5 \times 1) \\ = 1 \: newton$

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3 years ago

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Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg

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To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

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At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

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Where

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Our values are

$v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})$

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Replacing at the previous equation we have that the angular velocity is

$\omega = \frac{v}{R}$

$\omega = \frac{ 16.67}{0.25}$

$\omega = 66.67rad/s$

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

$\alpha = \frac{\omega}{t}$

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The energy of a photon was found to be 3.38 x 10-19 J. Planck's constant is 6.63 x 10-34 J. S. Which color of light corresponds

GalinKa [24]

Answer:

The correct option is (c).

Explanation:

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3 years ago