The amount remaining at the end of 5 half-lives is 7.81×10¹³ g
From the question given above, the following data were obtained:
- Half-life (t½) = 5730 years
- Original amount (N₀) = 2.5×10¹⁵ g
- Number of half-lives (n) = 5
- Amount remaining (N) =?
The amount remaining can be obtained as follow:
N = 1/2ⁿ × N₀
N = 1/2⁵ × 2.5×10¹⁵
N = 1/32 × 2.5×10¹⁵
N = 0.03125 × 2.5×10¹⁵
N = 7.81×10¹³ g
Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g
Learn more about half-life: brainly.com/question/25783920
Answer:
K = 0.0003 s⁻¹
Explanation:
The reaction is
2N₂O₅ = 4NO₂ + O₂
The equilibrium is
![K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]](https://tex.z-dn.net/?f=K%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7Bdt%7D%20%5C%5C%5Cint%5Climits%5Ey_x%20%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7B%7D%20%5C%2C%20%3D-2k%5Cint%5Climits%5Et_0%20%7Bdt%7D%20%5C%2C%5C%5Cln%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-2kt%2Bln%5BN_%7B2%7D%20O_%7B5%7D%20%5D)
a plot is attached
From the plot, the slope is -0.0006
-2 * K = -0.0006
K = 0.0003 s⁻¹
Answer:
<h2>100°C is the boiling point of water in degrees Celsius</h2>
All rivers erode the land over which they pass rendering a more gradual radiant to surrounding areas overtime.
Answer:
Stalagmites
Sinkholes
Stalacites
Explanation:
These features are created because the ground water dissolves solid rocks and move the solid rocks, dissolve solutions beneath the ground water gradually and therefore enlarging the cracks, which eventually form a cave. Ground water carries minerals which are then deposited and can form stalagmites or stalactites. If a stalactite and stalagmite combine together, they usually form a column.
