What are the answer choices?
Answer:
In this case, the system doesn't be affected by the pressure change. This means that nothing will happen
Explanation:
We can answer this question applying the Le Chatelier's Principle. It says that changes on pressure, volume or temperature of an equilibrium reaction will change the reaction direction until it returns to the equilibrium condition again.
The results of these changes can define as:
Changes on pressure: the reaction will move depending the quantity of moles on each side of the reaction
Changes on temperature: The reaction will move depending on if it's endothermic or exothermic
Changes on volume: The reaction will move depending the limit reagent and the quantity of moles on each side of the reaction
In the exercise, they mention a change on pressure of the system at constant temperature (that means the temperature doesn't change). As Le Chatelier Principle's says, we must analyze what happens if the pressure increase or decrease. If pressure increase the reaction will move on the side that have less quantity of moles, otherwise, if the pressure decreases the reaction will move to the side that have more quantity of moles. In this case, we can see that both sides of the equation have the same number of moles (2 for the reactants and 2 for the products). So, in this case, we can conclude that, despite the change on pressure (increase or decrease), nothing will happen.
Well, its a very simple process actually. Here is how it works;
When molecular hydrogen, also known as H2, and oxygen, also known as O2, are combined and are able to react together, energy is released and the molecules of the hydrogen and the oxygen. These can combine to form either water or hydrogen peroxide, depending on how the chemicals mix.
I hope I made your day a little easier,
Have a great day and happy Halloween!
Answer: The weight of the object on earth =441N
Weight of the object on moon = 72N
Answer:
K ^+ , CO3 ^2-
Explanation:
The compound is potassium trioxocarbonate(IV).
It contains cation (potassium ion) and acid radical ( trioxocarbonate (IV) ion).
Since K is in group 1 of the periodic table, it loses one electron to form ion i.e K^1. trioxocarbonate IV ion has a charge of 2-.and so the ions of the compound are as shown in the answer above.
