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julia-pushkina [17]
3 years ago
7

Which explains the basis of the Biuret test? a. Under base conditions, copper ions bind to the amino groups of proteins and chan

ge color. b. Iodine fits into the coils of starch polymers and changes color. c. A blue dye binds to protein and changes color.d. Sudan III dye binds to lipids and changes color.

Chemistry
2 answers:
nasty-shy [4]3 years ago
7 0

Answer:Answer: Under base conditions, copper ions bind to amino groups of proteins and change colour.

Explanation: Biuret test is a general test for detecting the presence of a peptide bond in a compound. It is a test for proteins. Amino acids are joined together in proteins by peptide bonds. Copper ions from blue alkaline solution of CuSO4 react with amino groups of proteins to give a violet colored complex called a biuret compound

Ugo [173]3 years ago
3 0

Answer:A

Explanation:

In the Biuret test, the copper ions bind covalently to the amino groups as shown in the image to form a violet complex. This violet complex is responsible for the colour change as shown

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If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?
Mazyrski [523]

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
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3 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

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hope this helps!

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