Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
If we write the first integer as the variable n, all numbers that come after it can be written as n+1, n+2, etc.
so the sum of four consecutive integers is:
sum = n + (n+1) + (n+2) + (n+3)
if we simplify:
sum = 4n +6
and if we want to know what the first integer is, we can re-write the equation as:
= n
and that is your answer.
Answer:
c. There is a vertical asymptote at x = pie
d. f(x) is undefined when sin x=0
Step-by-step explanation:
The given function is 
.
This is the reciprocal of the sine function;
This function is not defined when
This implies that there is a vertical asymptote at 
because 
.
Answer:
x < 4
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
Step 2: Subtract x from both sides.
Step 3: Subtract 6 from both sides.
Step 4: Multiply both sides by 4/(-1).
<span>To get the Least Common Multiple (LCM) of 37 and 12 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
<span><span>37: 37</span><span>12: 223 </span><span>LCM: 22337</span></span>The Least Common Multiple (LCM) is: 2 x 2 x 3 x 37 = 444</span><span> </span>
