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Arturiano [62]
4 years ago
5

The graph represents the path of an object thrown with a horizontal velocity from a certain height. What is the form of the grap

h?
A. a parabola with the vertex at (0,0) and a negative value for a
b.a parabola with the vertex at (0,0) and a positive value for a
c.an inverse graph
d.a linear graph

Physics
2 answers:
ValentinkaMS [17]4 years ago
8 0
I belive the answer is a

Strike441 [17]4 years ago
4 0

Answer:

A. a parabola with the vertex at (0,0) and a negative value for a

Explanation:

The path of an object thrown with a horizontal velocity from a certain heigth is the path of a projectile, and it is a parabolic path. It is the resultant of two independent motions:

- a horizontal uniform motion, with constant horizontal velocity

- a vertical accelerated motion, with constant acceleration (equal to the gravitational aceleration) towards the ground

Due to the fact that conventionally the positive direction of the vertical axis is taken as upward, the acceleration of the vertical motion is directed downward, so toward negative direction, so the value of a (acceleration) is negative.

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Alina [70]

Answer:

13.5 J

Explanation:

mass of ball, m = 3 kg

maximum height, h = 2.8 m

initial speed, u = 8 m/ s

Angle of projection, θ

use the formula of maximum height

H = \frac{u^{2}Sin^{2}\theta }{2g}

2.8 = \frac{8^{2}Sin^{2}\theta }{2\times 9.8}

Sin θ = 0.926

θ = 67.8°

The velocity at maximum height is u Cosθ = 8 Cos 67.8 = 3 m/s

So, kinetic energy at maximum height

K=\frac{1}{2}mv^{2}

K = 0.5 x 3 x 3 x 3

K = 13.5 J

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4 years ago
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6 0
3 years ago
I need help find how much tension is in the string????
Nikitich [7]

Answer:

When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????

Hence, in such a case the tension will be equal to the centrifugal force.

Formula for tension = centrifugal force = mv2/r.

So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)

The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)

Explanation:

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The answer is c......
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3 years ago
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