<span>Subtract the forces in the horizontal direction from the forces in the vertical direction.</span>
Answer:
197.76 m
Explanation:
r = Radius of the path = 20.6 km = 
= The angle subtended by moon = 
Distance traveled is given by



The distance traveled by the jet is 197.76 m
To start with solving this
problem, let us assume a launch angle of 45 degrees since that gives out the
maximum range for given initial speed. Also assuming that it was launched at
ground level since no initial height was given. Using g = 9.8 m/s^2, the
initial velocity is calculated using the formula:
(v sinθ)^2 = (v0 sinθ)^2
– 2 g d
where v is final
velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m
Rearranging to find for
v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>
<span>v0 = 10.383 m/s</span>
The answer is to u question is: C
Answer:
a) 7.02 W/m²
b) 1.53 J
Explanation:
Given
Amplitude of the electric wave, = 72.7 V/m
Area of flow, A = 0.0211 m²
Time taken, t = 10.3 s
To calculate the Intensity, S. We use the formula
I = E(rms)² / (cμ), where
E(rms) = E / √2 = 72.7 / √2
E(rms) = 72.7 / 1.4142
E(rms) = 51.41
c = 2.99*10^8
μ = 1.26*10^-6
I = 51.41² / [(2.99*10^8) (1.26 x 10^-6)]
I = 2642.99 / 376.74
I = 7.02 W/m²
U = energy = IAt
U = (7.02) * (0.0211) (10.3) J = 1.53 J