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3 years ago

11

__________ carries carcinogens into the lungs

2 answers:

guapka [62]3 years ago

7 0

The answer is Tobacco Smoke and Marijuana Smoke.

larisa [96]3 years ago

6 0

Tobacco smoking is an unhealthy habit which can cause cancer due to the presence of more than 5000 chemicals, some of which are carcinogens (a chemical that causes cancer). It is the smoke itself, that carries carcinogens to the lungs and can eventually lead to the development of diseases such as lung cancer.

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You tie a cord to a pail of water, and you swing the pail in a vertical circle of radius 0.600 m. what minimum speed must you gi

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Hrre si yen nserrras

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3 years ago

Which statement is true of stellar evolution?

noname [10]

There are no true statements at all on the list of choices
that you included with the question.

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3 years ago

Which best contrasts Newton's and Einstein's ideas?

Len [333]

Answer:

Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.

Explanation:

Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.

Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.

This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.

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3 years ago

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Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.84 keV from the co

ElenaW [278]

Answer:

λ = 65.6 pm

Explanation:

Given that

λo = 65 pm

The initial energy of the electron

$E_o=\dfrac{hC}{\lambda_0 }$

Now by putting the values

$E_o=\dfrac{hC}{\lambda_0 }$

$E_o=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{65\times 10^{-12}}$

$E_o=3.05\times 10^{-15}\ J$

$E_o=\dfrac{3.05\times 10^{-15}}{1.6\times 10^{-19}\times 10^3}\ KeV$

Eo=19.06 KeV

Given that kinetic energy KE= 0.84 KeV

Therefore the final energy

E= Eo - KE

E = 19.06 - 0.84 KeV

E= 18.22 KeV

The wavelength λ can be find as

$E=\dfrac{hC}{\lambda}$

$\lambda=\dfrac{hC}{E}$

$\lambda=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{19.06 \times 10^3\times 1.6\times 10^{-19}}$

λ = 6.56 x 10⁻¹¹ m

λ = 65.6 pm

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3 years ago

What makes the Moon completely dark during a lunar eclipse?

Andru [333]

Answer:

Thank me mark me brainliest pls

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2 years ago

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