The frictional force is 218.6 N
Explanation:
The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.
There are two forces acting along this direction:
- The component of the weight parallel to the incline, downward along the plane, of magnitude
where
m = 46 kg is the mass
is the acceleration of gravity
is the angle of the incline
- The (static) frictional force, acting upward, of magnitude
Since the block is in equilibrium, we can write
And substituting, we find the force of friction:
Learn more about frictional force along an inclined plane:
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There are some more like Time - second (s)
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Electric current - ampere (A)
Temperature - kelvin (K)
Luminous intensity - candela (cd)
Answer:
accelerate / increase speed OR decelerate / decrease speed OR stop B1
change direction / move in a curve o.w.t.t.e
Explanation:
accelerate / increase speed OR decelerate / decrease speed OR stop B1
change direction / move in a curve o.w.t.t.e
The model bridge captures all the structural attributes of the real bridge, at a reduced scale.
Part a.
Note that volume is proportional to the cube of length. Therefore the actual bridge will have 100^3 = 10^6 times the mass of the model bridge.
Because the model bridge weighs 50 N, the real bridge weighs
(50 N)*10^6 = 50 MN.
Part b.
The model bridge matches the structural characteristics of the actual bridge.
Therefore the real bridge will not sag either.