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3 years ago

13

You tie a cord to a pail of water, and you swing the pail in a vertical circle of radius 0.600 m. what minimum speed must you gi

ve the pail at the highest point of the circle if no water is to spill from it?

1 answer:

omeli [17]3 years ago

6 0

Hrre si yen nserrras

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What happens to a light wave when it travels from air into glass?

tino4ka555 [31]

Light is refracted when it crosses the interface from air to glass in which it moves more slowly.
Since the light speed changes at the interface, the wave length of the light must change too. The wave length decreases as the light enter the medium and the light wave changes direction.

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3 years ago

If we are viewing the atom in such a way that the electron's orbit is in the plane of the paper with the electron moving clockwi

Anastaziya [24]

Answer:

The magnitude of the electric field is $5.1 \times 10^{11} \frac{N}{C}$

Explanation:

Given:

Charge of electron $q = 1.6 \times 10^{-19}$ C

Separation between two charges $r = 5.3 \times 10^{-11}$ m

For finding the magnitude of the electric field,

$E= \frac{kq}{r^{2} }$

Where $k = 9 \times 10^{9}$

$E = \frac{9 \times 10^{9} \times 1.6 \times 10^{-19} }{(5.3 \times 10^{-11} )^{2} }$

$E = 5.1 \times 10^{11}$ $\frac{N}{C}$

Therefore, the magnitude of the electric field is $5.1 \times 10^{11} \frac{N}{C}$

5 0

4 years ago

A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t

Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

$KE = PE$

$\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}$

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

$q_{1,2}$ = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

$q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}$

Replacing,

$q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}$

$q_2 = 3.6531nC$

Therefore the charge on the sphere is 3.6531nC

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3 years ago

Brainly help this kid cause why not -_-!

ludmilkaskok [199]

Answer:

The answer is 3; Zero

Explanation:

It is to remembered that at critical temperature all three phases of liquid are at equilibrium and the surface tension is zero at this temperature.

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2 years ago

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How to make an uncharged particle positively charged

AlekseyPX

Answer:

If a neutral atom gains electrons, then it will become negatively charged. If a neutral atom loses electrons, then it become positively charged.

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3 years ago