You tie a cord to a pail of water, and you swing the pail in a vertical circle of radius 0.600 m. what minimum speed must you gi
1 answer:
You might be interested in
Answer:5.04*10^2joules
Explanation:
Answer:
0.069 J
Explanation:
mass of first ball (M1) = 0.839 kg
mass of second ball (M2) = 0.839 kg
initial velocity of first ball (U1) = 0.406 m/s
initial velocity of second ball (U2) = 0 m/s
For head on elastic collisions of equal masses, the velocities of the masses always changes.and this has also been clearly stated in the question. Hence the velocity if mass A will interchange with that of mass B after collision.
therefore
final velocity of first ball (V1) = 0 m/s
final velocity of second ball (V2) = 0.406 m/s
kinetic energy of second ball after collision = 0.5m
= 0.5 x 0.839 x 0.406 x 0.406 = 0.069 J