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3 years ago

What makes the Moon completely dark during a lunar eclipse?

Physics

2 answers:

Andru [333]3 years ago

8 0

Answer:

Thank me mark me brainliest pls

madreJ [45]3 years ago

4 0

The moon does not have any light of its own it’ shines because its surfaces reflects sunlight.

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kenny6666 [7]

Answer:

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Explanation:

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3 years ago

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What is angular frequency

Firlakuza [10]

Measures angular displacement per unit time.

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3 years ago

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A car can go from 0 m/s to 38 m/s in 4.5 seconds. If a net force of 6570 N acted on

masha68 [24]

The Mass of the car = 782.1 Kg

The mass of the car is calculated as follows:

Mass = Force/ acceleration

The force on the car = 6570 N

The acceleration of the car, a = 38 - 0/4.5

acceleration = 8.44 m/s²

Mass of the car = 6570/8.44

Mass of the car = 782.1 Kg

In conclusion, the mass of the car is obtained from the acceleration and force on the car.

Learn more about mass and acceleration at: brainly.com/question/19385703

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3 0

2 years ago

In punting a football, the kicker tries to maximize both the distance of the kick and its "hang time"—the time that the ball is

Alex787 [66]

Answer:

v₀ = 26.17 m/s

Explanation:

R = Xmax = 50 yards = (50 yards)*(0.9144 m / 1 yard) = 45.72 m

t = 5 s (Time of Flight)

we can apply the equation:

R = V₀x*t ⇒ V₀x = R / t = 45.72 m / 5 s ⇒ V₀x = 9.144 m/s

then we use the equation of Time of Flight:

t = 2*V₀y / g ⇒ V₀y = g*t / 2 = (9.81 m/s²)*(5 s) / 2 ⇒ V₀y = 24.525 m/s

Finally we apply

v₀ = √(V₀x² + V₀y²) ⇒ v₀ = √(9.144² + 24.525²) m/s

⇒ v₀ = 26.17 m/s

3 0

3 years ago

Is it possible to produce a continuous and oriented aramid fiber–epoxy matrix composite having longitudinal and transverse modul

gregori [183]

Answer:

It is not possible to produce continued and oriented fiber.

Explanation:

To solve the problem it is necessary to take into account the concepts related to Fiber volume ratio. The amount of fiber in a fiber reinforced compound corresponds directly to the mechanical properties of the compound. Given the fiber volume fraction, the theoretical elastic properties of a compound can be determined. The elastic modulus of a compound in the fiber direction of a unidirectional compound can be calculated using the following equation:

$E = (1-V_f)E_m+V_fE_f$

Where,

E is the longitudinal modulus of Elasticity

$V_f$ is the fiber volume ratio

$E_m$ is the elastic modulus of the matrix

$E_f$ is the elastic modulus of the fibers

We need to consult the table of characteristics of Fibers and Reinforcements of Materials, in which they specify that the modulus of elasticity of the aramid fiber-epoxy is

$E_f = 131Gpa$

Moreover from the statement,

$E = 35Gpa$

$E_m = 3.4Gpa$

Replacing in the previous equation,

$35 = 3.4 (1-V_f)+131V_f$

$V_f = 0.25 \rightarrow longitudinal$

To make the comparison we now calculate the Fiber volume ratio through the transverse elastic modulus,

$E = \frac{E_mE_f}{(1-V_f)E_f+V_fE_f}$

Our values are given in this case as:

$E = 5.17Gpa\\E_m = 3.4Gpa \\E_f = 131Gpa$

Replacing,

$5.17 = \frac{3.4*131}{(1-V_f)(131)+V_f*3.4}$

$V_f = 0.351 \rightarrow transversal$

From both cases it is possible to conclude that it is not possible to produce a fiber of the specified material in a continuous and oriented manner, as long as the volume fraction is different in the different cases.

5 0

3 years ago