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worty [1.4K]
2 years ago
15

What makes the Moon completely dark during a lunar eclipse?

Physics
2 answers:
Andru [333]2 years ago
8 0

Answer:

Thank me mark me brainliest pls

madreJ [45]2 years ago
4 0
The moon does not have any light of its own it’ shines because its surfaces reflects sunlight.
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A rocket is launched straight up from the earth's surface at a speed of 1.80×104 m/s .part awhat is its speed when it is very fa
balandron [24]
We can solve the problem by using the law of conservation of energy.

When the rocket starts its motion from the Earth surface, its mechanical energy is sum of kinetic energy and gravitational potential energy:
E_i = K_i + U_i =  \frac{1}{2} m v_i^2 + (- \frac{GM}{r} )
where
m is the rocket's mass
v_i = 1.8 \cdot 10^4 m/s is the rocket initial speed
G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant
M=5.97 \cdot 10^{24} kg is the Earth's mass
r= 6.37 \cdot 10^6 m is the distance of the rocket from the Earth's center (so, it corresponds to the Earth's radius)

The mechanical energy of the rocket when it is very far from the Earth is just kinetic energy (because the gravitational potential at infinite distance from Earth is taken to be zero):
E_f = K_f =  \frac{1}{2} mv_f ^2
where v_f is the final speed of the rocket.

By equalizing the initial energy and the final energy, we can find the final velocity:
\frac{1}{2} mv_i ^2 -  \frac{GM}{r} = \frac{1}{2}m v_f^2
v_f =  \sqrt{v_i^2 -  \frac{GM}{r} } =1.41 \cdot 10^4 m/s
3 0
3 years ago
Read 2 more answers
A small remote-control car with a mass of 1.65 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow
Reil [10]

Answer:

N=63.69N

Explanation:

The normal force exerted on the car by the walls of the cylinder at the bottom of the vertical circle will be such that when substracted to the weight it must give the centripetal force, since at that point on the vertical F_{cp}=N-W=N-mg

We also know that the equation for the centripetal force is:

F_{cp}=ma_{cp}=\frac{mv^2}{r}

Mixing both equations we get:

N-mg=\frac{mv^2}{r}

N=mg+\frac{mv^2}{r}

Which for our values means:

N=(1.65Kg)(9.8m/s^2)+\frac{(1.65Kg)(12m/s)^2}{(5m)}=63.69N

8 0
3 years ago
What is the speed of a wave that has a frequency of 45 Hz and a wavelength of 0.1 meters?
Yuri [45]
<span>λν=c
(wavelength x frequency = speed)

speed = 45 x 0.1
= 4.5 m/s</span>
6 0
3 years ago
Read 2 more answers
Which use combustion to release thermal energy?
julia-pushkina [17]
Heat of combustion.<span> The calorific value is the total energy released as heat when a substance undergoes complete combustion with oxygen under standard conditions. The chemical reaction is typically a hydrocarbon or other organic molecule reacting with oxygen to form carbon dioxide and water and release heat.</span>
8 0
3 years ago
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Steam enters a well-insulated nozzle at 200 lbf/in.2 , 500F, with a velocity of 200 ft/s and exits at 60 lbf/in.2 with a velocit
Ede4ka [16]

Answer:

386.2^{\circ}F

Explanation:

We are given that

P_1=200lbf/in^2

P_2=60lbf/in^2

v_1=200ft/s

v_2=1700ft/s

T_1=500^{\circ}F

Q=0

C_p=1BTU/lb^{\circ}F

We have to find the exit temperature.

By steady energy flow equation

h_1+v^2_1+Q=h_2+v^2_2

C_pT_1+\frac{P^2_1}{25037}+Q=C_pT_2+\frac{P^2_2}{25037}

1BTU/lb=25037ft^2/s^2

Substitute the values

1\times 500+\frac{(200)^2}{25037}+0=1\times T_2+\frac{(1700)^2}{25037}

500+1.598=T_2+115.4

T_2=500+1.598-115.4

T_2=386.2^{\circ}F

7 0
3 years ago
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