Perimeter:
p = 2b + 2h = 68
b = 4h - 6 (per problem statement)
substituting for b in the perimeter equation:
p = 2(4h - 6) + 2h = 68
(2)(4h) - (2)(6) + 2h = 68
8h - 12 + 2h = 68
10h - 12 = 68
10h = 68 + 12
10h = 80
h = 80/10
h = 8
b = 4(8) - 6 = 32 - 6 = 26
p = 2(26) + 2(8)
p = 52 + 16 = 68 . . . [OK]
b = 26 cm
h = 8 cm
Answer:
um what do u need
Step-by-step explanation:
Answer:
θ = 49.4584°
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] cosθ = adjacent over hypotenuse
- Inverse Trig
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Angle θ = ?
Adjacent Leg = 13
Hypotenuse = 20
<u>Step 2: Find Angle</u>
- Substitute in variables [cosine]: cosθ = 13/20
- Inverse Trig: θ = cos⁻¹(13/20)
- Evaluate: θ = 49.4584°
Answer:
Step-by-step explanation:
x + 12 = y
x = y - 12
Answer:
Area of PSTK = 50
Step-by-step explanation:
△SPK:
SK = 13, PK = 12
13^2 - 12^2 = SP^2
SP = 5
(8 + 12) /2 x 5 = 50
