Question

A car is moving 5.82 m/s when it accelerates at 2.35m/s^2 for 3.25s. how far does it travel?

Answer 1

Answer:

Distance, s = 31.32 meters

Explanation:

It is given that,

Initial velocity of the car, u = 5.82 m/s

Acceleration of the car, $a=2.35\ m/s^2$

Time taken, t = 3.25 s

We need to find the distance travelled by the car. Let s denotes the distance covered by the car. It can be calculated using the second equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

$s=5.82\times 3.25+\dfrac{1}{2}\times 2.35\times(3.25)^2$

s = 31.32 meters

So, the distance travelled by the car is 31.32 meters. Hence, this is the required solution.

Answer 2

U: 5.82 m/s
a: 2.35 m/s^2
t: 3.25 s
s: distance traveled