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iVinArrow [24]
3 years ago
13

Describe a situation where your body can act as a lightning conductor.

Physics
1 answer:
Naddika [18.5K]3 years ago
7 0

When someone is struct by lightning, the electricity passes through the body, into the earth. Here, our body acts as a lightning conductor to complete the earthing process.

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K value in base units for coloumbs law
Crazy boy [7]

Answer:

The constant k has the value. k = 8.99 × 10 9 N ⋅ m 2 /C 2.

5 0
2 years ago
Which figure represents the electric field lines of two positive point charges?
Naddik [55]

Electric field lines of positive charges are always radially outwards

So here all field lines must have tendency to move out radially as well as two field lines never intersects with each other

So here field lines also do not intersects with each other

So overall the figure C is perfectly representing the field lines of two positive charges as these lines are not intersecting and also originating from two positive charges.

So answer must be

<u><em>FIGURE C</em></u>

7 0
3 years ago
La intensidad de corriente que circula por un conductor es 2μA. ¿Que tiempo demoraran 5x1013 electrones en cruzar una determinad
VikaD [51]

Answer:

t = 4 seconds

Explanation:

The question is "The intensity of current flowing through a conductor is 2μA. How long will it take 5x1013 electrons to cross a certain cross section of the conductor? "

Current, I=2\ \mu A=2\times 10^{-6}\ A

No of electrons, n=5\times 10^{13}

We need to find how long will it take to given no of electrons to cross a certain cross section of the conductor.

Electric current,

I=\dfrac{q}{t}

t is time

Also, q = ne

I=\dfrac{ne}{t}\\\\t=\dfrac{ne}{I}\\\\t=\dfrac{5\times 10^{13}\times 1.6\times 10^{-19}}{2\times 10^{-6}}\\\\t=4\ s

So, it will take 4 seconds.

5 0
3 years ago
Satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an
Volgvan

Answer:

0.63

Explanation:

We are given that

Radius of earth,R_E=6370 km

Radius of orbit A,R_A=7590+6370=13960 km

Radius of orbit B,R_B=6370+15800=22170 km

We have to find the ratio of the potential energy of satellite B to that of satellite A in orbit.

Potential energy of orbit A=U_A=-\frac{GM}{R_A}=-\frac{GM}{13960}

Potential energy of orbit  B=U_B=-\frac{GM}{R_B}=-\frac{GM}{22170}

\frac{U_B}{U_A}=\frac{13960}{22170}=0.63

Hence,the ratio of the potential energy of satellite B to that of satellite A in orbit=0.63

8 0
4 years ago
An electron with a charge value of 1.6x10^-19 C is in the presence of an electric field of 300 N/C when located between a pair o
Blababa [14]

(1.6 x 10⁻¹⁹ C) x (300 N/C) = <em>4.8 x 10⁻¹⁷ Newton</em>

<em></em>

6 0
4 years ago
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