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Andru [333]
2 years ago
5

HELP! how did michael jordan influence future basketball players to make prodcuts?

Physics
2 answers:
nataly862011 [7]2 years ago
5 0

Answer:

By encouraging them.

Explanation:

#CARRYONLEARNING

maksim [4K]2 years ago
5 0

Answer:

His ability to soar to the basket and do things we'd never before seen captured the world's attention and helped make basketball more of a global sport than it had ever been.  His reverse layups, slam dunks, and fadeaway shots were exciting to say the least.

Explanation:

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If you were to move to the Canadian North Woods, what adaptations or behavioral changes would you make?
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How many days does it take for a free to grow?
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3 years ago
What occurs when light bends while passing from one medium to another?
Levart [38]

Answer:So the answer is B

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2 years ago
A charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a th
Mila [183]

Answer:

x = a + \frac{a\sqrt2}{\sqrt3 - \sqrt2}

Explanation:

Position of charge 3q is x = 0

position of charge -2q is x = a

so here we know that

when two charges are of opposite nature then the electric field will be zero on the line joining the two charges at the position near to smaller magnitude charge

So here the electric field will be zero if the field due to 3q is counterbalanced by field due to -2q

so here we can say

\frac{k(3q)}{(r+a)^2} + \frac{k(-2q)}{r^2} = 0

\frac{3}{(r + a)^2} = \frac{2}{r^2}

\frac{r+a}{r} = \sqrt{\frac{3}{2}}

1 + \frac{a}{r} =\sqrt{\frac{3}{2}}

\frac{a}{r} = \frac{\sqrt3 - \sqrt2}{\sqrt2}

so we will have

r = \frac{a\sqrt2}{\sqrt3 - \sqrt2}

so the x coordinate of this position is given as

x = a + \frac{a\sqrt2}{\sqrt3 - \sqrt2}

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3 years ago
A wire with a resistance of 20 Ω is connected to a 12-V battery. What is the current flowing through the wire?
Mice21 [21]
Current is 0.6 Amps should be right
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Read 2 more answers
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