In my opinion, it would be coke because of all the pressure
The density of hematite ore is <u>4.78 g/cm³</u>.
Let the mass of the ore be m₁ , the volume of the flask <em>V</em>, total mass of water and ore M, mass of water be m₂, density of ore ρ₁ and the density of water be ρ₂.
Density of a substance is defined as the mass per unit volume.
The mass of water in the flask is given by,
![M-m_1= (109.3 g)-(70.7 g)=38.3 g](https://tex.z-dn.net/?f=%20M-m_1%3D%20%28109.3%20g%29-%2870.7%20g%29%3D38.3%20g%20)
Calculate the volume V₂ of the water in the flask.
![V_2=\frac{m_2}{\rho_2} =\frac{38.3 g}{0.997 g/cm^3} = 38.4cm^3](https://tex.z-dn.net/?f=%20V_2%3D%5Cfrac%7Bm_2%7D%7B%5Crho_2%7D%20%20%3D%5Cfrac%7B38.3%20g%7D%7B0.997%20g%2Fcm%5E3%7D%20%20%3D%2038.4cm%5E3%20)
Calculate the volume V₁occupied by the ore in the flask.
1 ml is equivalent to 1 cm³.
Calculate the density of the ore.
![\rho_1=\frac{m_1}{V_1}=\frac{70.7 g}{14.8 cm^3} = 4.78g/cm^3](https://tex.z-dn.net/?f=%20%5Crho_1%3D%5Cfrac%7Bm_1%7D%7BV_1%7D%3D%5Cfrac%7B70.7%20g%7D%7B14.8%20cm%5E3%7D%20%3D%204.78g%2Fcm%5E3%20%20%20)
The density of the hematite ore is found to be 4.78 g/.cm³
Answer:
because the electricity always looking for a way to get to the ground
The work done in lifting an object to a height of 2 m is equal to two times the weight of the object. W = 2×mg
<h3>
Explanation:</h3>
Consider the mass of object to be m kg. The amount of work done to lift an object depends on the force required and the distance to which force is applied. To lift the object to a height of 2 m; Let F be the amount of force applied.
..................(1)
Where,
W=Work done
F= Amount of applied force
h=Height to which object is to be lifted
Applied force is equal to the weight of the object. Therefore,
..............(2)
Where,
m=Mass of the object
g=gravitational acceleration
Substituting (2) in (1), we get
![W=m\times g\times h](https://tex.z-dn.net/?f=W%3Dm%5Ctimes%20g%5Ctimes%20h)
For height = 2 m, ![W = m\times g\times 2](https://tex.z-dn.net/?f=W%20%3D%20m%5Ctimes%20g%5Ctimes%202)
![W=2\times m\times g = 2\times Weight\ of\ object](https://tex.z-dn.net/?f=W%3D2%5Ctimes%20m%5Ctimes%20g%20%3D%202%5Ctimes%20Weight%5C%20of%5C%20object)
The work done in lifting an object to a height of 2 m is equal to twice the weight of the object.
Sure enough !
Acceleration means any change in speed OR DIRECTION of motion.
So if something is moving in a circle or around a curve, even at constant
speed, its direction is changing, so acceleration is not zero.