Answer:
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Explanation:
The car's final speed in m/s after the acceleration is 30.
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<u>Given the following data:</u>
- Initial velocity, U = 0 m/s (since the cars starts from rest)
- Acceleration, a = 3 meter per seconds square.
To find the car's final speed in m/s after the acceleration, we would use the first equation of motion;
Mathematically, the first equation of motion is given by the formula;

<em>Final speed, V </em><em>=</em><em> 30 m/s</em>
Therefore, the car's final speed in m/s after the acceleration is 30.
Read more: brainly.com/question/8898885
Answer: Formula for Acceleration Due to Gravity
These two laws lead to the most useful form of the formula for calculating acceleration due to gravity: g = G*M/R^2, where g is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance.please mark as brainliest
Explanation:
Answer:
h’ = 1/9 h
Explanation:
This exercise must be solved in parts:
* Let's start by finding the speed of sphere B at the lowest point, let's use the concepts of conservation of energy
starting point. Higher
Em₀ = U = m g h
final point. Lower, just before the crash
Em_f = K = ½ m
energy is conserved
Em₀ = Em_f
m g h = ½ m v²
v_b =
* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved
initial instant. Just before the crash
p₀ = 2m 0 + m v_b
final instant. Right after the crash
p_f = (2m + m) v
the moment is preserved
p₀ = p_f
m v_b = 3m v
v = v_b / 3
v = ⅓ 
* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together
Starting point. Lower
Em₀ = K = ½ 3m v²
Final point. Higher
Em_f = U = (3m) g h'
Em₀ = Em_f
½ 3m v² = 3m g h’
we substitute
h’=
h’ =
h’ = 1/9 h