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Tom [10]
3 years ago
8

Identify the areas on the image where the force of repulsion is the least.

Physics
2 answers:
timofeeve [1]3 years ago
7 0

Answer:

here in the first figure the force of repulsion will be least between two SOUTH poles at the ends of the magnet

while in the other diagram the repulsion force of left end or repulsion force of each right end will be least on each other

Explanation:

the force of repulsion is always between two similar type of poles between two magnets

So when similar poles are close to each other then it will have more repulsion force while if the similar poles are far apart then the repulsion force will be smaller

So here in the first figure the force of repulsion will be least between two SOUTH poles at the ends of the magnet

while in the other diagram the repulsion force of left end or repulsion force of each right end will be least on each other

ArbitrLikvidat [17]3 years ago
3 0

Each magnet has a north pole and a south pole. We know that, from having played with bar magnets in our childhood, that a magnet's north pole will repel another magnet's north pole and attract its south pole.

From this diagram it is easy to see that the two lower bar magnets not only repel each other, but they are quite attracted to each other since their north and south poles are close together.

Therefore the region between the lower two magnets has the least force of repulsion.

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Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is  less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

  From the question we are told that

     The random sample is n = 15

       The mean weight is \= x = 3.8\  ounce

        The standard deviation is  \sigma = 0.5 \ ounce

         The  level of significance is  \alpha  = 0.05

       

So

   The  null hypothesis is  H_o : \mu \ge 4

     The alternative hypothesis is H_a : \mu < 4

Generally the critical value which a bench mark to ascertain whether the null hypothesis is  true or false is mathematically represented as

            t_{0.05} = 1.79

This value is  obtained from  the critical value table

Generally the test statistics is mathematically represented as

                Test \ Statistics (ST)  = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} }  }

           =>  ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }

                ST = - 1.79

So since ST is less than t_{0.05}  then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

  Thus the true mean weight is less than 4

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Velocity, instead, can be in any direction: When an object is speeding up is in the same direction as the acceleration, while if it is slowing down, it has just the opposite.

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