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Gwar [14]
2 years ago
9

 With _______ insurance, the insured agrees to pay a specific premium each year until death. 

Physics
2 answers:
AlekseyPX2 years ago
8 0
Your answer will be D whole-life 
VashaNatasha [74]2 years ago
5 0
D. Whole-lfie

Many call it whole-life, but they usually are a limited age. Usually up to 95yrs old
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A. lunar phases result from the changing lunar mass. Let me know if this helped.
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3 years ago
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An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.80 kW. A receiving antenna 7
Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I=\frac{P_{avg}}{A}

I=\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}

I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

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7 0
3 years ago
Different _ of an element have different numbers of neutrons?
natali 33 [55]

Answer:

Isotopes

Explanation:

Your welcome

4 0
3 years ago
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A velocity selector in a mass spectrometer uses an electric field of 4.4 x 105 V/m. What magnetic field strength (in Tesla) is n
Brut [27]

Answer:

  B = 9.16 10⁻²  T

Explanation:

The speed selector is a configuration where the electric and magnetic force has the opposite direction, which for a specific speed cancel

       q v B = q E

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       B = E / v

Let's calculate

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5 0
3 years ago
n the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 400 N and makes an a
Leto [7]

Since the ladder is standing, we know that the coefficient of friction is at least something. This [gotta be at least this] friction coefficient can be calculated. As the man begins to climb the ladder, the friction can even be less than the free-standing friction coefficient. However, as the man climbs the ladder, more and more friction is required. Since he eventually slips, we know that friction is less than what's required at the top of the ladder.

 

The only "answer" to this problem is putting lower and upper bounds on the coefficient. For the lower one, find how much friction the ladder needs to stand by itself. For the most that friction could be, find what friction is when the man reaches the top of the ladder.

Ff = uN1

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Fy = 0 = N1 – 400 – 864

N1 = 1264 N

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3 years ago
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