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Veronika [31]
3 years ago
12

How do you think the temperature difference between the beakers relates to the rate of heat transfer?

Physics
1 answer:
Bogdan [553]3 years ago
8 0

Answer and Explanation:

The rate (in W) at which heat energy moves from the more blazing article to the colder item increments with the temperature distinction between the items.  

The more noteworthy the temperature contrast, the more prominent the rate at which exchange of heat energy takes place.

Thus the temperature difference between the beakers relates in the same manner as described above.

The exchange of heat energy continues until a thermal equilibrium is attained.

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The force exerted on the tires of a car that directly accelerate it along a road is exerted by the
azamat

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

<h3>What is force?</h3>

Force is defined as the product of mass and acceleration of an object.

Friction is defined as the force that resists the movement of an object over another.

Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

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7 0
2 years ago
What came first the chicken or the egg
maxonik [38]

Answer:

The Egg

Explanation:

personally the Chicken who would lay the egg would have to come from an Egg itself, then It would have to grow up and then Produce an egg that will produce a chicken and so on.

6 0
3 years ago
A student decides to move a box of books into her dormitory room by pulling on a rope attached to the box. She pulls with a forc
____ [38]

Answer:

Part a)

a = 0.36 m/s^2

Part b)

a = -1.29 m/s^2

Explanation:

Force applied by the student on the box is 80 N at an angle of 25 degree

so here two components of the force on the box is given as

F_x = Fcos25

F_x = 80 cos25 = 72.5 N

F_y = Fsin25

F_y = 80 sin25 = 33.8 N

now in vertical direction we can use force balance for the box to find the normal force on it

F_n + F_y = mg

F_n = (25)(9.81) - 33.8

F_n = 211.45 N

now kinetic friction on the box opposite to applied force due to rough floor is given as

F_k = \mu F_n

F_k = (0.300)(211.45) = 63.44 N

now the net force on the box in forward direction is given as

F_{net} = F_x - F_k

F_{net} = 72.5 - 63.44 = 9.065 N

now the acceleration of the box is given as

a = \frac{F_{net}}{m}

a = \frac{9.065}{25} = 0.36 m/s^2

Part b)

when box is pulled up along the inclined surface of angle 10 degree

now the two components of the force will be same along the inclined and perpendicular to inclined plane

F_x = 72.5 N

F_y = 33.8 N

now force balance perpendicular to inclined plane is given as

F_n + F_y = mgcos\theta

F_n = (25)(9.81)cos10 - 33.8 = 207.7 N

now the friction force opposite to the motion on the box is given as

f_k = \mu F_n

f_k = (0.300)(207.7) = 62.3 N

now the net pulling force along the inclined plane is given as

F_{net} = F_x - F_k - mgsin10

F_{net} = 72.5 - 62.3 - (25)(9.81)sin10

F_{net} = -32.38 N

now the box will decelerate and it is given as

a = \frac{F_{net}}{m}

a = \frac{-32.38}{25} = -1.29 m/s^2

7 0
4 years ago
How are some types of collisions different from others?
lyudmila [28]
There are two general types of collisions, inelastic and elastic. 
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Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering) 
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3 years ago
What are three types of mechanical weathering
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Three types of mechanical weathering are Frost Wedging, Exfoliation, and Biological weathering. Hope this helps!!! ;)
4 0
3 years ago
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