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Veronika [31]
3 years ago
12

How do you think the temperature difference between the beakers relates to the rate of heat transfer?

Physics
1 answer:
Bogdan [553]3 years ago
8 0

Answer and Explanation:

The rate (in W) at which heat energy moves from the more blazing article to the colder item increments with the temperature distinction between the items.  

The more noteworthy the temperature contrast, the more prominent the rate at which exchange of heat energy takes place.

Thus the temperature difference between the beakers relates in the same manner as described above.

The exchange of heat energy continues until a thermal equilibrium is attained.

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Which of the following methods has led to the earliest discoveries of massive planets orbiting near their parent stars a. detect
Mrac [35]

Answer:

c. detecting the gravitational effect of an orbiting planet (The Wobble"") by looking for the Doppler shifts in the star's spectrum

Explanation:

In a solar system the mass of the star and planets affect each other's orbital  movements. The center of gravity of a star and a planet is inside the star. This causes the star to be closer and farther from the Earth at different times. Due to this wobble the star appears to be red shifted when it is farther and blue shifted when it is closer.

When the mass of the planet is high, like a hot Jupiter it causes more wobble i.e., change in radial velocity. This makes it easier to detect the planet. The earliest hot Jupiter found by this method is the planet 51 Pegasi b.

3 0
3 years ago
When a person speaks, a sound intensity is generated that is 600 times greater than when the person whispers. What is the differ
Charra [1.4K]

Answer:

Originally :  Level = log I / I0

Currently: Level = 10 log I / I0

Level = 10 log 600 = 10 * 2.78 = 27.8

Note the term 1 bel = 10 decibels

5 0
2 years ago
Which of the following is NOT an indicator of a physical change?
S_A_V [24]

Answer:

1.  C.  The change is easily reversible

2. A.  a physical change

Explanation:

Happy Holidays

8 0
2 years ago
17. (a) Will the electric field strength between two parallel conducting plates exceed the breakdown strength for air ( 3.0×106
sleet_krkn [62]

Answer:

Explanation:

Distance between plates d = 2 x 10⁻³m

Potential diff applied = 5 x 10³ V

Electric field = Potential diff applied /  d

= 5 x 10³  / 2 x 10⁻³

= 2.5 x 10⁶ V/m

This is less than  breakdown strength for air  3.0×10⁶ V/m

b ) Let the plates be at a separation of d .so

5 x 10³ / d = 3.0×10⁶ ( break down voltage )

d = 5 x 10³  / 3.0×10⁶

= 1.67 x 10⁻³ m

= 1.67 mm.

5 0
3 years ago
Help, please
Mice21 [21]

Answer:

A and A

Explanation:

see paper for work! :)

8 0
2 years ago
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