A la romana me voy a beber Buchanan que tiene sangre gitana
Answer:
1] 8500000 = <u>8.5 × 10⁶</u>
2] .000072 = <u>7.2 × 10⁻⁵</u>
3] 5.3 × 10⁴ = <u>53000</u>
4] 2.8 × 10⁻³ = <u>0.0028</u>
5] Velocity = ![\frac{distance}{time}](https://tex.z-dn.net/?f=%5Cfrac%7Bdistance%7D%7Btime%7D%20)
V = ![\frac{50}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B50%7D%7B10%7D%20)
<u>V = 5 m/s</u>
6] Acceleration = ![\frac{V1-V2}{time}](https://tex.z-dn.net/?f=%5Cfrac%7BV1-V2%7D%7Btime%7D%20)
A = ![\frac{30-15}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B30-15%7D%7B3%7D%20)
A = ![\frac{15}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B3%7D%20)
<u>A = 3 m/s²</u>
Data:
The charge of a body depends on the amount of electrons it gains or loses. Q = n * e, where "Q" is charge, "n" is the number of plus or minus electrons, and "e" is the fundamental charge of an electron
![1,6 * 10 ^{-19}C](https://tex.z-dn.net/?f=1%2C6%20%2A%2010%20%5E%7B-19%7DC)
<span>. To know if the body has gained or lost, we look at the signal of its charge, remembering that the electron is negative. The charge of the body is 4 μC (positive), so there is a lack of electrons!
Q = 4 </span>μC →
![Q = 4*10^{-6}](https://tex.z-dn.net/?f=Q%20%3D%204%2A10%5E%7B-6%7D)
![e = 1,6 * 10 ^{-19}C](https://tex.z-dn.net/?f=e%20%3D%201%2C6%20%2A%2010%20%5E%7B-19%7DC)
![n = ?](https://tex.z-dn.net/?f=n%20%3D%20%3F)
<span>
We have:
</span>
![Q = n*e](https://tex.z-dn.net/?f=Q%20%3D%20n%2Ae)
![n = \frac{Q}{e}](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BQ%7D%7Be%7D%20)
![n = \frac{4*10^{-6}}{1,6 * 10 ^{-19}}](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B4%2A10%5E%7B-6%7D%7D%7B1%2C6%20%2A%2010%20%5E%7B-19%7D%7D%20)
![n = 2,5*10^{-6-(-19)}](https://tex.z-dn.net/?f=n%20%3D%202%2C5%2A10%5E%7B-6-%28-19%29%7D)
![n = 2,5*10^{-6+19}](https://tex.z-dn.net/?f=n%20%3D%202%2C5%2A10%5E%7B-6%2B19%7D)
Explanation:
For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.
Three known temperature scales;
- Kelvin scale
- Celcius scale
- Fahrenheit scale
Kelvin scale Celcius scale Fahrenheit scale
Freezing point 273K 0°C 32°F
Melting point 373K 100°C 212°F