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BlackZzzverrR [31]
3 years ago
12

Can each polyatomic ion be treated as a unit when balancing the chemical equation

Chemistry
1 answer:
marysya [2.9K]3 years ago
3 0
Yes. You can either treat the entire polyatomic ion as a unit or separate the elements in the polyatomic ion. Pay attention the parentheses and subscripts, though. Those can confuse people a lot. I personally find it easier to just treat it as a whole unit.  
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Which of the following is the best example of an open system? (2 points)
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Read 2 more answers
The measured value 24.00 g has an uncertainty of?
Orlov [11]

Answer:

±0.005 g

Explanation:

The uncertainty depends on whether the measurement was obtained manually or digitally.

1. Manual

The minimum uncertainty is ±0.01 g.

It may be greater, depending on random or personal errors

2. Digital

Most measurements of mass are now made on digital scales.

A digital device must always round off the measurement it displays.

For example, if the display reads 20.00, the measurement must be between 20.005 and 19.995 (±0.005).

If the measured value were 20.006, the display would round up to 20.01.

If the measured value were 19.994, the display would round down to 19.99.

The uncertainty is ±0.005 g.

The scale shown below would display a mass of 20.00 g

6 0
4 years ago
2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en
dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

lnA=0.4728

logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

Learn more about Arrhenius equation here-

brainly.com/question/12907018

#SPJ4

5 0
1 year ago
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