For the work-energy theorem, the work done by the engine on the car is equal to the variation of kinetic energy of the car:
where m=1167 kg is the mass of the car,
is the initial speed and
is the final speed.
Putting numbers into the equation, we find:
Answer:
the Jack speed is greater than the Nas speed
v₁ = 2.08 m / s > v2 = 1.85 m / s
Explanation:
For this exercise we can find the average speed of each of the boys, the average speed is defined as the displacement in the time interval
v = x / t
Jack.
It tells us that it travels x = 15 km in a time of t = 2 h
let's reduce the magnitudes to the SI system
x = 15 km (1000 m / 1 km) = 15 10³ m
t = 2 h (3600 s / 1 h) = 7200 s
let's calculate
v₁ = 15 10³/7200
v₁ = 2.08 m / s
Nas travels a distance of x = 10 km in a time of t = 1.5 h
x = 10 km = 10 10³ m
t = 1.5 h (3600s / 1h) = 5400 s
let's calculate the speed
v2 = 10 10³/5400
v2 = 1.85 m / s
From these results we can see that the Jack speed is greater than the Nas speed
Electrostatics is described as the study of electric charges that can be collected and held in place.
The above given statement is a true st
Answer:
The average current density at the position of the area.
Explanation:
Current density is the vector whose magnitude is electric current in the cross sectional area. Current density is vector quantity which is measured in amperes. The average current density is dependent on the electric current flow. It has perpendicular direction of flow and scalar magnitude.
N2+3H2->2NH3
When 3 moles of H2 react, they produce 2 moles of NH3
3 moles of H2 have a mass of 2.02 g
2 moles of NH2 have a mass of 17.0 g
So when 2.02 g H2 react, they produce 17.0 g NH3
If 26.3g H2 react with a yield of 100%, we expect…
2.02g H2_____17.0gNH3
26.3g H2_____x=221gNH3
So now let’s calculate the percentage:
221gNH3_________100%
79.0gNH3_________x=79.0*100/221=35.7%
