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2 years ago

Write about Archimedes principle

Physics

2 answers:

Schach [20]2 years ago

8 0

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics.

nexus9112 [7]2 years ago

5 0

Answer:

When a body is immersed fully or partially in a fluid, it experience is an upward force that is equal to the weight of the fluid displaced by it.

<h3>Applications:</h3>

In designing ships and submarines.
Lactometers used to determine the purity of sample of milk.
Hydrometer is used to determine the density of liquids.

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about how much more energy is released in a 6.5 richter magnitude earthquake than in one with magnitude 5.5?

OverLord2011 [107]

Answer:

For example, an earthquake of magnitude 5.5 releases about 32 times as much energy as an earthquake measuring 4.5. Another way to look at this is that it takes about 900 magnitude 4.5 earthquakes to equal the energy released in a single 6.5 earthquake.

Explanation:

8 0

3 years ago

A projectile is fired upward with an initial speed vo on an airless world. A short time later, it comes back down and has a fina

Zinaida [17]

Answer:

$W_{grav} < 0$

Explanation:

When a projectile is fired upwards with some initial speed then the it reaches the top of the projectile and then falls back to the ground.

According to the question we need to find the work done by the gravity which is acting downwards for the projectile when it is at a position just about to hit the ground in course of falling down.

As we know that work is given as:

$W=F.s\cos\theta$

here:

$F=$ force of gravity on the object (which is acting downwards)

$s=$ displacement of the object

Here the work done by the gravity at an instant just before the projectile hits the earth will be negative as the displacement is in the direction opposite to the force of gravity.

7 0

4 years ago

You drive in a straight line at 22 m/s for 12 miles, then at 30 m/s for another 12 miles. (a) How does your average speed sav co

Setler [38]

Answer:

Explanation:One method of calculating average speed is to divide the total distance by the total time spent

d1=d2= 12 miles

d1=d2= 19312.1 m

$t1=\frac{d1}{u1} \\t1=19312.1/22\\t1=877.8 secs$

$t2=\frac{d2}{u2} \\t2=19312.1/30\\t2=673.7 secs$

$u_a=\frac{d1+d2}{t1+t2} \\u_a=25.385 m/s$

There is slight difference between the average speeds due to the reason that average speed is not just the midpoint of the speed but is the total distance traveled by total time.

6 0

3 years ago

In figure 16-2 is the temperature of the material within the cylinder greatest during the intake stroke, compression stroke, pow

erastovalidia [21]

Technically, we have no way of knowing that without seeing Figure 16-2.
So the question should be reported for incomplete content. But I'm
going to take a wild stab at it anyway.

There's so much discussion of 'cylinder' and 'strokes' in the question,
I have a hunch that it's talking about the guts of a 4-stroke internal
combustion gasoline engine.

If I'm right, then the temperature of the material within the cylinder is
greatest right after the spark ignites it. At that instant, the material burns,
explodes, expands violently, and drives the piston down with its stiff shot
of pressure.

This is obviously happening because of the great, sudden increase in
temperature when the material ignites and explodes.

It hits the piston with pressure, which leads directly to the power stroke.

5 0

3 years ago

A Huge water tank is 2m above the ground if the water level on it is 4.9m high and a small opening is there at the bottom then t

lapo4ka [179]

Answer:

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

Explanation:

Let assume the existence of a line of current between the water tank and the ground and, hence, the absence of heat and work interactions throughout the system. If water is approximately at rest at water tank and at atmospheric pressure ( $P_{atm}$ ), then speed of efflux of the non-viscous water is modelled after the Bernoulli's Principle:

$P_{1} + \rho\cdot \frac{v_{1}^{2}}{2} + \rho\cdot g \cdot z_{1} = P_{2} + \rho\cdot \frac{v_{2}^{2}}{2} + \rho\cdot g \cdot z_{2}$

Where:

$P_{1}$ , $P_{2}$ - Water total pressures inside the tank and at ground level, measured in pascals.

$\rho$ - Water density, measured in kilograms per cubic meter.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Water speeds inside the tank and at the ground level, measured in meters per second.

$z_{1}$ , $z_{2}$ - Heights of the tank and ground level, measured in meters.

Given that $P_{1} = P_{2} = P_{atm}$ , $\rho = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ , $v_{1} = 0\,\frac{m}{s}$ , $z_{1} = 6.9\,m$ and $z_{2} = 4.9\,m$ , the expression is reduced to this: