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3 years ago

O Which two elements will be the most alike and why?

Physics

2 answers:

katrin [286]3 years ago

8 0

LITHIUM AND SODIUM BECAUSE THEY ARE BOTH METALS SODIUM IS AN EARTH METAL WHILE SODIUM IS AN ALKALINE EARTH METAL

Pavel [41]3 years ago

5 0

C. Because they are in the same group, so they have the same number of valence (outer) electrons

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Bond [772]

Answer:

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Explanation:

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3 years ago

Type O blood is known as the universal donor why is this so?

bagirrra123 [75]

Because their blood cells could be transfused to any blood type
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3 years ago

Read 2 more answers

A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 3.84 m/s

JulijaS [17]

Answer:

the train is moving at the speed of v = 1.79 m/s

Explanation:

given,

rain drop is falling vertically down with the speed of = 3.84 m/s

angle of the rain drop = 25°

tan θ = $\dfrac{v}{u}$

tan 25° = $\dfrac{v}{3.84}$

v =3.84 × tan 25°

v = 1.79 m/s

hence, the train is moving at the speed of v = 1.79 m/s

3 0

3 years ago

The table shows information about four students who are running around a track. Which statement is supported by the information

murzikaleks [220]

Answer:

Mohammed has less kinetic energy than Autumn

Explanation:

The kinetic energy of each student is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the student

v is the speed of the student

Let's use the formula above to calculate the kinetic energy of each student:

- Autumn: $K=\frac{1}{2}(50 kg)(4 m/s)^2=400 J$

- Mohammed: $K=\frac{1}{2}(57 kg)(3 m/s)^2=256.5 J$

- Lexy: $K=\frac{1}{2}(53 kg)(3 m/s)^2=238.5 J$

- Chiang: $K=\frac{1}{2}(64 kg)(5 m/s)^2=800 J$

Therefore, by looking at the numbers, we see that the correct answer is

Mohammed has less kinetic energy than Autumn

7 0

3 years ago

Read 2 more answers

A 1250-kg compact car is moving with velocity v1 =36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448

MA_775_DIABLO [31]

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 i + 12.7 j ) m/s) + (448 kg) ((13.8 i + 10.2 j ) m/s) = ((1250 + 448) kg) v

where v is the velocity of the system. Solve for v :

v = ((1250 kg) ((36.2 i + 12.7 j ) m/s) + (448 kg) ((13.8 i + 10.2 j ) m/s)) / (1698 kg)

v ≈ (30.3 i + 12.0 j ) m/s

7 0

3 years ago