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Gemiola [76]
3 years ago
15

Does the sun give plants the nutrients to grow yes or no!!!

Physics
1 answer:
Vlad1618 [11]3 years ago
4 0
Your is going to be yes.
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A man rides up in an elevator at 12 m. He gains 6500 J of gravitational potential energy. what is the man's mass?
iren2701 [21]

Answer:

We know that potential energy of a body;

= mass(m)× gravitational acceleration(g) × height(h)

Lets find out the mass of the body

P.E. = mgh

=> 6500J = mass × 9.8m/s^2 × 12m

=>6500J = mass × ( 9.8 × 12 ) × ( m/s^2 × m)

=> 6500 Nm = m × 117.6 × m^2 / s^2

=> 6500/117.6 Ns^2/m = mass [°.° Ns^2/m = kg]

=> 55.272 Kg = mass

Therefore the mass of the body = 55.272 kg ~ <em>6</em><em>0</em><em> </em><em>k</em><em>g</em><em> </em>(Ans)

Hope it helps you

6 0
3 years ago
Martes
sdas [7]

Explanation:

(9) Acceleration due to gravity is defined as the acceleration between two massive bodies when they are moving under free fall.

The relation between g and G is given by :

g=\dfrac{GM}{r^2}

Where

G is universal gravitational constant

M is mass of the earth

r is distance

(10) The unwanted product that can toxify the crops are called weeds. To control weeds, a chemical called weedicides are sprayed in the field. Some other methods to control them are Ploughing or tilling of soil etc.

5 0
3 years ago
What are the three types of mechanical waves?
Black_prince [1.1K]

Answer:

I'm sure its transverse, longitudinal and surface

Explanation:

sorry if I'm wrong

4 0
2 years ago
PLEASE HELP PLEASE HELP ME PLEASE HELP ME ​
klemol [59]

Answer:24

Explanation:

7 0
2 years ago
Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electr
svlad2 [7]

Answer:

Electric field, E = 45.19 N/C

Explanation:

It is given that,

Surface charge density of first surface, \sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2

Surface charge density of second surface, \sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2

The electric field at a point between the two surfaces is given by :

E=\dfrac{\sigma}{2\epsilon_o}

E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}

E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.

6 0
3 years ago
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