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3 years ago

What is the formula for wheel and axel

Physics

1 answer:

aleksley [76]3 years ago

3 0

Answer: MA= Radius of wheel divided by Radius of Axle

Explanation:

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A block of mass m = 4.8 kg slides from left to right across a frictionless surface with a speed Vi=7.3m/s. It collides with a bl

nirvana33 [79]

Answer:

The speed of the 11.5kg block after the collision is V≅4.1 m/s

Explanation:

ma= 4.8 kg

va1= 7.3 m/s

va2= - 2.5 m/s

mb= 11.5 kg

vb1= 0 m/s

vb2= ?

vb2= ( ma*va1 - ma*va2) / mb

vb2= 4.09 m/s ≅ 4.1 m/s

7 0

3 years ago

I’m so confused someone help

Lena [83]

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Brainly?

4 0

3 years ago

Read 2 more answers

Only the smallest particles of soil can be displaced by suspension because

mote1985 [20]

The choices can be found elsewhere and as follows:

a. they are so small that they stay close to the ground due to the attractive properties of charged soil particles.

b. they are easily carried by the wind.

c. they easily dissolve in liquid droplets.

d. it is easier for then to roll along the small crevices in the ground.

I think the correct answer from the choices listed above is option B. Only the smallest particles of soil can be displaced by suspension because they are so small that they are easily carried by the wind. Hope this answers the question. Have a nice day. Feel free to ask more questions.

7 0

3 years ago

Read 2 more answers

A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in

Karolina [17]

Answer:

$\tau = 1256.5\ N.m$

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

$\alpha = \dfrac{\omega_f-\omega_i}{t}$

$\alpha = \dfrac{125.66-0}{5}$

α = 25.13 rad/s²

Torque given to the flywheel.

$\tau = I \alpha$

$\tau = 50\times 25.13$

$\tau = 1256.5\ N.m$

Torque of the given flywheel is equal to $\tau = 1256.5\ N.m$

7 0

3 years ago

How is the combined gas law used to calculate changes in pressure, temperatures, and/or volume for a fixed amount of gas?

nalin [4]

Answer:

Let's start by considering the ideal gas law:

$pV=nRT$

where

p is the gas pressure

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature

This equation can also be rewritten as

$\frac{pV}{T}=nR$

Now, if we consider a fixed amount of gas, this means that the number of moles (n) is constant. So we can rewrite the equation as

$\frac{pV}{T}=const.$

And therefore, if we consider a gas undergoing a certain transformation from 1 to 2, we can write

$\frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2}$

where 1 indicates the conditions of the gas at the beginning and 2 the conditions of the gas after the process. So, the change in pressure/temperature/volume of the gas can be found by using this equation.

5 0

3 years ago