You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the
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Answer:
Final temperature, T2 = 314.9 Kelvin
Explanation:
Given the following data:
Mass = 0.9kg
Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K
Quantity of heat = 120,000 J
Specific heat capacity = 4182 j/kgK
To find the final temperature;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making dt the subject of formula, we have;
Substituting into the equation, we have;
dt = 31.9K
Now, the final temperature T2 is;
But, dt = T2 - T1
T2 = dt + T1
T2 = 31.9 + 283
T2 = 314.9 Kelvin