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3 years ago

13

Between the orbits of Mars and Jupiter, several thousand small objects called asteroids move in nearly circular orbits around th

e Sun. Consider an asteroid that is spherically shaped with radius r and density 2400 kg/m3 .
Part A) You find yourself on the surface of this asteroid and throw a baseball at a speed of 30 m/s . If the baseball is to travel around the asteroid in a circular orbit, what is the largest radius asteroid on which you are capable of accomplishing this feat?

Part B) After you throw the baseball, you turn around and face the opposite direction and catch the baseball. How much time T elapses between your throw and your catch?

1 answer:

vazorg [7]3 years ago

7 0

Answer:

Lo siento si no entiendes español, pero si lo sabes, necesito estos puntos. Te han robado un punto

Explanation:

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at a particular instant a hot air balloon is 100m in the air and decending at a constant speed of 2m/s at this exact instant a g

labwork [276]

<h2>She will find the ball at a horizontal distance of 86.4 m from landed location</h2>

Explanation:

Consider the vertical motion of ball

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 2 m/s

Acceleration, a = 9.81 m/s²

Displacement, s = 100 m

Substituting

s = ut + 0.5 at²

100 = 2 x t + 0.5 x 9.81 xt²

4.905t² + 2t - 100 = 0

t = 4.32 s or t = -4.72 s

After 4.32 seconds the ball reaches ground.

Now we need to find horizontal distance traveled by ball in 4.32 seconds.

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 20 m/s

Acceleration, a = 0 m/s²

Time, t = 4.32 s

Substituting

s = ut + 0.5 at²

s = 20 x 4.32 + 0.5 x 0 x 4.32²

s = 86.4 m

She will find the ball at a horizontal distance of 86.4 m from landed location

5 0

4 years ago

A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad

Anna71 [15]

Answer:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

$a_{r} = \omega^{2}\cdot R$

Where:

$\omega$ - Angular speed, measured in radians per second.

$R$ - Radius of rotation, measured in meters.

The angular speed is first determined:

$\omega = \frac{\pi}{30}\cdot \dot n$

Where $\dot n$ is the angular speed, measured in revolutions per minute.

If $\dot n = 3000\,rpm$ , the angular speed measured in radians per second is:

$\omega = \frac{\pi}{30}\cdot (3000\,rpm)$

$\omega \approx 314.159\,\frac{rad}{s}$

Now, if $\omega = 314.159\,\frac{rad}{s}$ and $R = 0.1\,m$ , the resultant acceleration is then:

$a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)$

$a_{r} = 9869.588\,\frac{m}{s^{2}}$

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

6 0

3 years ago

A ball rolls onto the path of your car as you drive down a quiet neighborhood street. To avoid hitting the child that runs to re

Ilya [14]

Answer:

a) F = -1035.385 N

b) Backwards

c) s = 15.60 m

Explanation:

Given information

$u$ = Initial Speed of Car = 15.0 m/s

$v$ = Final Speed of Car = 9.00 m/s

$t_{b}$ = Breaking Time = 1.30 s

$m$ = Mass of Car = 1040 kg

Part (a)

To find the force exerted on the car we use the following formula

$F = ma$

Where

$F$ = Force = unknown

$m$ = Mass of Car = 1040 kg

$a$ = Acceleration of Car / Deceleration of Car = unknown

To find the force (F) we need to first find the deceleration rate (a)

To find the deceleration rate we use the following formula

$a = \frac{v - u}{t}$

Inputting the given values

$a = \frac{15 - 9}{1.30} \\ a = -4.615$

To find the force

$F = ma \\ F = (1040)(-4.615) \\ F = (1040)(-4.615) \\ F = -1035.385 N$

Part (b)

Since the value of F is negative this means the the force was opposite the direction of motion, hence the force was backwards.

Part (c)

To find the total distance the car moved while braking we use the following formula

$v^2 = u^2 + 2as$

Where

$s$ = distance traveled

Inputting the values given

$(9)^2 = (15)^2 + 2(-4.615)s$

$s = 15.60 m$

6 0

3 years ago

The amount of force we need to move an object is proportional to the amount of work done - the __________ force used, the more w

Vanyuwa [196]

Answer:

stronger.

pls follow me.

7 0

3 years ago

2. Explain what happened to the electrons in an ion with a charge of +1.

Stella [2.4K]

Answer:

An atom always has the same number of electrons as protons. Electrons have an electric charge of -1 and protons have an electric charge of +1. Therefore, the charges of an atom's electrons and protons “cancel out.” This explains why atoms are neutral in electric charge.

Explanation:

7 0

3 years ago

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