1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatyana61 [14]
2 years ago
14

Which of these can produce an electric current?Required to answer. Single choice.

Physics
1 answer:
vivado [14]2 years ago
4 0

Answer:

last one which is; All the above.

You might be interested in
The ratio of output force is the what of a machine
Crazy boy [7]
The ratio of output force to the input force is generally the mechanical advantage of the machine.
7 0
3 years ago
An unbalanced force gives a 2.00 kg mass an acceleration of 5.00 m/s? What is the force applied to the object?​
valentinak56 [21]

Answer:

10N

Explanation:

Equation: ΣF = ma

Fapp = ma

Fapp = (2kg)(5m/s^2)    (im guessing you mean 5.00 m/s^2 not m/s)

Fapp = 10*kg*m/s^2

Fapp = 10N

5 0
2 years ago
Importance of choke coil?<br><br>​
Verdich [7]

Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.

Explanation:

8 0
2 years ago
Below is a single strand of DNA, what is the complementary base pair for the strand?
GREYUIT [131]
The complementary base pair is:
TTC, CTG, AGT, CTA.
5 0
2 years ago
50POINTS! Find the orbital speed of a satellite in a circular orbit 1700km above the surface of the Earth. M_earth 5.97e24kg, r_
ivolga24 [154]
<h2>Answer: 7020.117 m/s</h2>

Explanation:

The velocity of a satellite describing a circular orbit is<u> constant</u> and defined by the following expression:  

V=\sqrt{G\frac{M}{R}} (1)  

Where:  

G=6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}} is the gravity constant

M_{Earth}=5.97{10}^{24}kg the mass of the massive body around which the satellite is orbiting, in this case, the Earth .

R=r_{Earth}+h=8080000m the radius of the orbit (measured from the center of the planet to the satellite).  

This means the radius of the orbit is equal to <u>the sum</u> of the average radius of the Earth r_{Earth} and the altitude of the satellite above the Earth's surface h.

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).

Now, rewriting equation (1) with the known values:

V=\sqrt{(6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}})\frac{5.97{10}^{24}kg}{8080000m}}

V=7020.117\frac{m}{s}  

6 0
3 years ago
Read 2 more answers
Other questions:
  • HELPPPP MEEE!!! 15 POINTS
    9·1 answer
  • 3.   The main difference between speed and velocity involves
    6·1 answer
  • A parallel-plate capacitor connected to a battery becomes fully charged. After the capacitor from the battery is disconnected, t
    9·1 answer
  • The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
    6·1 answer
  • Explain why radiation is dangerous for humans
    9·2 answers
  • How many distillation are there?​
    13·1 answer
  • A spring with a spring constant of 2.5 N/m is stretched by 2
    7·1 answer
  • Chris walks 25 m in the positive direction on a number line, then turns around and walks 15 m in the opposite direction. What is
    12·1 answer
  • Write the law of friction???​
    15·2 answers
  • What is radioactivity????​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!