The number of electrons it take to fill the mos formed from the combination of the 3s orbitals of two atoms simply is 14 electrons.
<h3>How electrons are distributed in the 3s orbitals.</h3>
The 3s orbital possess two different spherical nodes which is highly connected with the principal quantum number. In order words, it has 2 radial nodes. Also the shape of the 3s orbital is spherical in shape.
That being said, from the context of the above given task, the number of electrons which fill the mos formed from the combination of the 3s orbitals of two atoms is fourteen electrons.
However, the electron configuration of an atom simply is the arrangement of electrons in the electron shell or orbit of the atom of that element.
In conclusion, it can be deduced from above s orbital has a maximum of two electrons and this energy increases as the orbitals increases.
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A physical change has occured, Boiling water is a physical change not a chemical one, now if you're talking about the electric current, that had not changes either. it may rearrange the molecules, but it does not change the fundamental properties of the substance.
The answer is (3) pH 3 to pH 1. The pH is related to the concentration of H3O+ with the relationship: pH = -lg c(H+). So when concentration of H3O+ increase, the pH will decrease. And decrease 2 when when increase hundredfold. Because 100=10^2.
Answer: The volume for 0.850 mol of 
from a solution is 1700 mL.
The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Explanation:
Molarity is the number of moles of solute present in a liter of solution.
- As given moles of are 0.850 mol and molarity of solution is 0.5 M. Hence, its volume is calculated as follows.
Therefore, the volume for 0.850 mol of from a solution is 1700 mL.
- As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.
So, volume for LiOH solution is calculated as follows.
Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
