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2 years ago

The following formula relates 3 equantities: force(F),mass(m),and acceleration(a)

1 answer:

5 0

We know, Force = mass × acceleration

( i ) :

Given,
Force = 25 units
Mass = 10 units
Acceleration = ?

Solution,

Applying the formula of force,
➡ Force = mass × Acceleration

⏩ 25 = 10 × acceleration

⏩ 25 / 10 =acceleration

⏩ 2.5 units = acceleration

( ii ) :

Given,
Force = 25 units
Acceleration = 5 units
Mass =?

Solution :

Applying formula,
➡ Force = mass × acceleration

⏩ 25 = 5 × mass

⏩ 25 / 5 = mass

⏩ 5 units = mass

$\:$

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Someone please help!! Determine the intercept of the line.

hichkok12 [17]

Answers:

x intercept is (-7.5, 0)

y intercept is (0, 5.5)

=========================

How to get these answers:

Simply look at where the graph crosses the x axis to determine the x intercept. This is directly halfway between the -8 and -7, so the line crosses through -7.5 on the x axis meaning that the x intercept is located at (-7.5, 0)

Similarly, the y intercept is (0, 5.5) as it crosses exactly halfway between the 5 and 6 on the y axis.

Any point is of the form (x,y)

The x intercept always has y = 0. The y intercept always has x = 0.

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2 years ago

Read 2 more answers

In the diagram below, which distance represents the distance from point D to

11Alexandr11 [23.1K]

Answer
A.CD
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2 years ago

Juno boots 57 oranges in bags each bag holds 6 oranges use the area 2 divided

statuscvo [17]

Answer:

10 bags needed .......

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2 years ago

the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.

Bond [772]

Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671 = a1 + 42d

-806 = a1 + 51d

Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

-9d = 135

d = -15

Substitute for d in the first equation:

-671 = a1 + 42*-15

-671 = a1 - 630

a1 = -671 + 630 = -41.

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2 years ago

6300 and 530, 3 and 2 underlined Compare value The value 3 in____ is _____times

topjm [15]

Basically when reading the value of a digit we start from the right.
Digits from the right to the left are named as follows:
units......>no zeros/digits after them
tens......> 1 zero/digit after the digit
hundreds.......> 2 zeros/digits after the digit
thousands......> 3 zeros/digits after the digit
ten thousands.......> 4 zeros/digits after the digit
hundred thousands.........> 5 zeros/digits after the digit
million........> 6 zeros/digits after the digit

Applying this on the above mentioned numbers, we will find that the 3 represents the hundreds (300) in 6300 while it represent the tens (30) in 530.

The question is to find the difference between the two, which means we will subtract them:
difference = 300 - 30 = 270

The value 3 in 6300 is 270 times the value of 3 in 530

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2 years ago