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Orlov [11]
3 years ago
7

The following formula relates 3 equantities: force(F),mass(m),and acceleration(a)

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0
We know, Force = mass × acceleration


( i ) :

Given,
Force = 25 units
Mass = 10 units
Acceleration = ?


Solution,

Applying the formula of force,
➡ Force = mass × Acceleration

⏩ 25 = 10 × acceleration

⏩ 25 / 10 =acceleration

⏩ 2.5 units = acceleration




( ii ) :


Given,
Force = 25 units
Acceleration = 5 units
Mass =?



Solution :

Applying formula,
➡ Force = mass × acceleration

⏩ 25 = 5 × mass

⏩ 25 / 5 = mass

⏩ 5 units = mass



\:
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A shirt originally cost $39.38, but it is on sale for $31.50. What is the percentage decrease of the price of the shirt? If nece
seraphim [82]

Answer:

20%

Step-by-step explanation:

1. subtract the new price from the original price

39.38-31.50=7.88

2. divide the difference by the original number

7.88 ÷ 39.38=.2001

3. multiply this number by 100

(.2001)100=20%

5 0
3 years ago
Given that an American is a male, what is the probability that he prefers name-brand milk? b. Given that an American is a female
Evgesh-ka [11]

Answer:

a) 0.280

b) 0.300

c) No, preference is not independent of gender. Since the P(N) (0.29) is not equal to P(N|M) (0.28) and/or P(N|F) (0.30), the preference and gender are not completely, statistically independent. It's very close though.

Step-by-step explanation:

Let the probability that the somebody surveyed is a male be P(M)

Let the probability that somebody surveyed is female be P(F)

Let the probability that somebody surveyed picked the name-brand milk be P(N)

Let the probability that somebody surveyed picked the store-brand milk be P(St)

Let the probability that somebody surveyed picked the something else be P(So)

a) Given that an American is a male, what is the probability that he prefers name-brand milk = P(N|M) = 319/1138 = 0.280

b) Given that an American is a female, what is the probability that she prefers name-brand milk = P(N|F) = 341/1138 = 0.300

c) To investigate if the preference and gender are independent or not, we need the P(N)

P(N) = probability that an average an Average American (male or female) will prefer a nam-brand milk = 660/2276 = 0.290.

Since the P(N) (0.29) is not equal to P(N|M) (0.28) and/or P(N|F) (0.30), the preference and gender are not statistically independent. It's very close though.

3 0
3 years ago
What is the domain of the function on the graph?
Dennis_Churaev [7]

Answer:

All real numbers greater than or equal to -3

Step-by-step explanation:

First look at graph where the line points to which direction of the graph

And look for any closed or open circles in the graph

Since in the graph has a close circle at (-3,-2) meaning it includes that x-value for its domain.

With the graph going to positive infinity it states that the domain is all real numbers.

So in conclusion it has a domain of all real numbers greater than or equal to -3

5 0
3 years ago
The pair of points is on the graph of an inverse variation. Find the missing value. (1.6, 6) and (8, y) 0.03 30 1.2 0.83
ZanzabumX [31]
One may note that (1.6 , 6)  is just another way to say x = 1.6 when y = 6.

and that (8 , y) is another way to say x = 8 and y is who knows.

\bf \qquad \qquad \textit{inverse proportional variation}\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \textit{we know that }
\begin{cases}
x=1.6\\
y=6
\end{cases}\implies 6=\cfrac{k}{1.6}\implies 6(1.6)=k\implies 9.6=k
\\\\\\
\qquad therefore\qquad \boxed{y=\cfrac{9.6}{x}}
\\\\\\
\textit{when x = 8, what is \underline{y}?}\qquad y=\cfrac{9.6}{8}
3 0
2 years ago
Read 2 more answers
A man travels from town X to town Y at an average rate of 60 mph and returns at an average rate of 50 mph. He takes a 1/2 hour l
yawa3891 [41]
<span>Distance = d miles ; rate = 60 mph ; time = d/60 hrs

distance = d miles ; rate = 50 mph ; time = d/50 hrs
----------------------
Round-trip DATA:
distance = 2d miles ; rate = 55 mph ; time = (2d)/55 hrs
-----------------------------------------------------------
Equation:

Roundtrip time - other time = -1/2 hr
(2d)/55 - [(d/60)+(d/50)] = -1/2
(2d)/55 - [(110d)/(50*60)] = -1/2
---
600(2d) - 11[110d] = -16500
1200d - 1210d = -16500
-10d = -16500
distance = 1650 miles

Hope this helped :)</span>
3 0
3 years ago
Read 2 more answers
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