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devlian [24]
2 years ago
7

Find the number of moles of sodium hydroxide in 25cm3 solution of concentration 0,1 mol/dm3​

Chemistry
1 answer:
kozerog [31]2 years ago
3 0

Answer:

0.0025  moles

Explanation:

25cm^3 = 25/1000 dm^3

Conc = mol/dm^3

Mol = conc * dm^3

Mol = 0.1 * 25/1000

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Consider the following equilibrium:
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<u>Answer: </u>The equation which is wrong is K_p=K_c(RT)^{-5}

<u>Explanation:</u>

For the given reaction:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

The expression for K_c\text{ and }K_p is given by:

K_c=\frac{1}{[O_2]^3}

K_p=\frac{1}{[O_2]^3}

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between K_p\text{ and }K_c is given by the expression:

K_p=K_c\times (RT)^{\Delta n_g}

where,

\Delta n_g= number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

\Delta n_g = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for K_p is:

K_p=K_c\times (RT)^{-3}

Therefore, the equation which is wrong is K_p=K_c(RT)^{-5}

7 0
3 years ago
*URGENT*
DaniilM [7]

Answer:

d hope this helps u hhwjs GD jehehj

4 0
3 years ago
Read 2 more answers
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