Answer:
This question is incomplete, here's the complete question:
<em><u>"Suppose 0.0842g of potassium sulfate is dissolved in 50.mL of a 52.0mM aqueous solution of sodium chromate. Calculate the final molarity of potassium cation in the solution. You can assume the volume of the solution doesn't change when the potassium sulfate is dissolved in it. Round your answer to 2 significant digits."</u></em>
Explanation:
Reaction :-
K2SO4 + Na2CrO4 ------> K2CrO4 + Na2SO4
Mass of K2SO4 = 0.0842 g, Molar mass of K2SO4 = 174.26 g/mol
Number of moles of K2SO4 = 0.0842 g / 174.26 g/mol = 0.000483 mol
Concentration of Na2CrO4 = 52.0 mM = 52.0 * 10^-3 M = 0.052 mol/L
Volume of Na2CrO4 solution = 50.0 ml = 50 L / 1000 = 0.05 L
Number of moles of Na2CrO4 = 0.05 L * 0.052 mol/L = 0.0026 mol
Since number of moles of K2SO4 is smaller than number of moles Na2CrO4, so 0.000483 mol of K2SO4 will react with 0.000483 mol of Na2CrO4 will produce 0.000483 mol of K2CrO4.
0.000483 mol of K2CrO4 will dissociate into 2* 0.000483 mol of K^+
Final concentration of potassium cation
= (2*0.000483 mol) / 0.05 L = 0.02 mol/L = 0.02 M
Answer:
water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.
Explanation:
C. Theres decreased Biodiversity Most likely because of natural or human causes (deforistation)
Answer: i believe it is
602,000,000,000,000,000,000,000 atoms
Explanation:
6.02×1023 atoms/mole
Answer:
11.0 dm³
Explanation:
From the question,
Applying
PV= nRT............... Equation 1
Where P = pressure of oxygen gas, V = volume of oxygen gas, n = number of moles of oxygen, R = molar constant, T = Temperature.
make V the subeject of the equation
V = nRT/P............. Equation 2
But,
Number of mole (n) = Mass of oxygen(m)/Molar mass of oxygen(m')
n = m/m'....................... Equation 3
Substitute equation 3 into equation 2
V = mRT/Pm'............. Equation 4
Given: T = 28°C = (28+273) = 301 K, P = 0.998 torr = (0.998×0.00131579) = 1.3132 atm, m = 18.4 g
Constant: R = 0.082 atm.dm³/K.mol, m' = 32 g/mol.
Substitute these values into equation 4
V = (301×18.4×0.082)/(32×1.3132)
V = 454.1488/42.0224
V = 10.81 dm³
V = 11.0 dm³
