Answer:
Explanation:
Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:
Where 
and 
are the orbital periods of Mercury and Earth respectively. We have 
and 
. Replacing this and solving for
Answer:
intensity of the light that emerges from the three filters is 560.80 W/m²
Explanation:
Given data
intensity I = 1375 W/m2
angle 1 = 31.0°
angle 2 = 41.0°
to find out
intensity of the light that emerges from the three filters
solution
we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5 W/m2
so intensity after 2nd polarize pass = I 1st cos²(θ)
I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754) = 575.27 W/m2
and
intensity after 3rd polarize pass = I 2nd cos²(θ)
I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2
so that intensity of the light that emerges from the three filters is 560.80 W/m²
The correct response would be C. Carpenter hammering a nail. The carpenter is applying a force as he or she is hitting the surface of the nail with the hammer.
D) How fast you are moving
f = 10000N
distance moved = 20 m
work done = 10000*20 = 200000
