ANSWER:
What is the measured component of the orbital magnetic dipole moment of an electron with the values
(a) ml=3
(b )
ml= −4
a) -278 x 
J/T
b) 3.71 x J/T
STEP-BY-STEP EXPLANATION:
a) ml= 3
Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x J/T
b) ml= 3
Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x J/T
“Bonding molecular orbitals are formed by... in-phase combinations of atomic wave functions, and electrons in these orbitals stabilize a molecule.”
Answer:
n= | Shell | Maximum Number of Electrons
1 | 1st Shell | 2
2 | 2nd Shell | 8
3 | 3rd Shell | 18
4 | 4th Shell | 32
Explanation: cause :)
Input the atomic masses of Mg and P to give 134.84g/mol
Explanation:
The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance:
When dealing with an element the molar mass is the relative atomic mass expressed as g/mol.
For compounds, you add the atomic masses of the component atoms and you sum up.
You simply input the atomic mass of 3 atoms of Mg and 2 atoms of P
Atomic mass of Mg = 24.3g/mol
P = 30.97g/mole
Molar mass of Mg₃P₂ = 3(24.3) + 2(30.97) = 134.84g/mol
learn more:
Molar mass brainly.com/question/2861244
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Answer:
CH₄
Explanation:
To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.
Step 1: Determine the mass of the compound
The mass of the compound is equal to the sum of the masses of the elements that form it.
m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g
Step 2: Calculate the percent by mass of each element
%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%
%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%
Step 3: Divide each percentage by the atomic mass of the element
C: 74.8/12.01 = 6.23
H: 25.2/1.01 = 24.95
Step 4: Divide both numbers by the smallest one, i.e. 6.23
C: 6.23/6.23 = 1
H: 24.95/6.23 ≈ 4
The empirical formula of the hydrocarbon is CH₄.
