The heat that is required to raise the temperature of an object is calculated through the equation,
heat = mass x specific heat x (T2 - T1)
Specific heat is therefore calculated through the equation below,
specific heat = heat / (mass x (T2 - T1))
Substituting,
specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The value of specific heat from above equation is 0.838 J/g°C.
Answer:
= 3132.9 Joules
Explanation:
- Kinetic energy is the energy possessed by a body when in motion.
- Kinetic energy is calculated by the formula; K.E = 1/2 mV², where m is the mass of the body or object, and V is the velocity.
- Therefore kinetic energy depends on the mass and the velocity of the body or the object in motion.
In this case;
Kinetic energy = 0.5 × 0.018 kg × 590²
<u>= 3132.9 Joules</u>
C. Is your answer hope you have a wonderful day
Answer:
The energy transferred is 28.5 j
calculation
energy is calculate MCΔT formula where,
M(mass)= 6.30 grams
C(specific heat capacity)= 0.377 j/g
ΔT(change in temperature)= 32.0c- 20 c= 12 c
Energy is therefore= 6.30 g x 0.377 j/g /c x 12 c =28.5 j
