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2 years ago

15

If a scientist wants to make molecules move slower, what should they do? A. decrease their kinetic energy B. Transfer energy out

of them C. Put them in a freezer D. All of the above

2 answers:

kvv77 [185]2 years ago

7 0

The answer is D all of the abound

SVEN [57.7K]2 years ago

3 0

The answer is D because it’s D

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The chemical equation of photosynthesis includes 6o2. which best describes this substance?

LenaWriter [7]

The chemical equation of photosynthesis includes 6 $O_{2}$ . -----a gas produced during photosynthesis best describes this substance

Elaborate:

During photosynthesis plants use carbon dioxide, water and sunlight to make sugar (glucose) and a waste product, oxygen gas.

the equation of this process can be:

6 $CO_{2}$ + 6 $H_{2} O$ + light energy → $C_{6} H_{12} O_{6}$ + 6 $O_{2}$

carbon dioxide + water + light → glucose + oxygen

Is 6 $O_{2}$ a product of photosynthesis?

In photosynthesis, energy from light is used to convert carbon dioxide and water into glucose and oxygen. For 6 carbon dioxide and 6 water molecules, 1 glucose molecule and 6 oxygen molecules are produced.

What happens to sugar water oxygen and carbon dioxide during photosynthesis?

During photosynthesis, plants take in carbon dioxide and water from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose.

Learn more about photosynthesis:

brainly.com/question/19160081

#SPJ4

4 0

9 months ago

Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com

lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30 = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

5 0

3 years ago

Energy in a vacuum travels by ___.<br> A. radiation<br> B. conduction<br> C. convection

mariarad [96]

I think it’s radiation, that’s what i got from looking it up

8 0

2 years ago

Help please I will thank you

mart [117]

There should be 2 since there’s 2 D atoms in the reaction.

3 0

2 years ago

What is the hydronium ion concentration of a solution whose pH is 7.30

Assoli18 [71]

[ H₃O⁺] = 10 ^ - pH

[ H₃O⁺ ] = 10 ^ - 7.30

[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

hope this helps!

6 0

2 years ago