The velocity - time graph of a ball of mass 25g moving on road is as given below:
1 answer:
Assume that the ball rolls to the right.
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
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Answer:
Explanation:
We are asked to find the final velocity of the boat.
We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.
The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.
= 2.7 m/s
- a= 0.15 m/s²
- t= 12 s
Substitute the values into the formula.
Multiply the numbers in parentheses.
Add.
The final velocity of the boat is <u>4.5 meters per second in the positive direction.</u>