The velocity - time graph of a ball of mass 25g moving on road is as given below:
1 answer:
Assume that the ball rolls to the right.
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
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Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 .
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units .
In this case, you have:
- number of moles= 70 g×
= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
- volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)
Replacing in the definition of molarity:
Solving:
<u><em>Molarity= 2.5510 </em></u>
Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 .
Learn more about molarity:
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Answer:
Explanation:
From the Question we are told that:
Mass
Coefficient of kinetic friction
Generally the equation for Frictional force is mathematically given by
Generally the Newton's equation for Acceleration due to Friction force is mathematically given by
Therefore