Answer:
Coefficient of friction = 0.836
Explanation:
If v be the speed after one quarter of the circular path
v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8
tangential acceleration = 5.8 m/s²
radial acceleration = v² /r = 5.8
total acceleration = √2 x 5.8
m x√2 x 5.8 = m x g xμ
μ = √2 x 5.8 / 9.8 = 0.836
Answer:
<em><u>It can be a solid, liquid, gas</u></em><em><u>,</u></em><em><u>plasma</u></em><em><u>,</u></em><em><u>etc</u></em><em><u>. When waves travel through a medium, the particles of the medium are not carried along with </u></em><em><u>the</u></em><em><u> </u></em><em><u>wave</u></em><em><u>.</u></em><em><u>For example, water waves have to travel in water. Sound waves need a solid, a liquid or a gas to travel in.</u></em>
To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.
Answer:
The potential energy when it reads 40 N is 
Explanation:
From the question we are told that
The lowest reading of the spring balance is 0 N and this is at 0 cm = 0 m
The height reading of the spring balance is 60 N and this is at 20 cm = 0.20 m
Generally the length corresponding to the reading of 40 N is mathematically represented as

=> 
Generally the potential energy is mathematically represented as

Here
So

=> 