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Lemur [1.5K]
3 years ago
14

Why at the poles is the cenripetal accleration zero?

Physics
1 answer:
Pavel [41]3 years ago
7 0
The poles are essentially a fixed point.

I have so much to say but won't be able to articulate it in a succinct manner, sorry for keeping it short and sweet.
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<span>II.              </span>Irregular pearly glow

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<span>II.              </span>large bright gaseous

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<span>IV.             </span>rises above chromospheres

<span>V.                 </span>anchored to surface (sun’s surface)

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I did this in class I got 100%

7 0
3 years ago
Which two factors affect the amount of thermal energy an object has?
Scrat [10]

Answer:

Explanation:

1) The average kinetic energy of the particles of the object  or the temperature of the substance.

2) The mass of the object.

8 0
3 years ago
A 1.50-m cylinder of radius 1.10 cm is made of a complicated mixture of materials. Its resistivity depends on the distance x fro
MArishka [77]

Answer:

Resistance = 3.35*10^{-4} Ω

Explanation:

Since resistance R = ρ\frac{L}{A}

whereas \rho(x) = a + bx^2

resistivity is given for two ends. At the left end resistivity is 2.25* 10^{-8} whereas x at the left end will be 0 as distance is zero. Thus

2.25*10^{-8} = a + b(0)^2\\ 2.25*10^{-8} = a + 0 \\2.25*10^{-8} = a

At the right end x will be equal to the length of the rod, so x = 1.50\\8.50*10^{-8} = (2.25*10^{-8}) + ( b* (1.50)^2 )\\8.50*10^{-8} - (2.25*10^{-8}) = b*2.25\\\frac{6.25*10^{-8}}{2.25}  = b\\b = 2.77 *10^{-8}

Thus resistance will be R = ρ\frac{L}{A}

where A = π r^2

so,

R = \frac{8.50*10^{-8} * 1.50}{3.14*(1.10*10^{-2})^2} \\R=3.35 * 10 ^{-4}

6 0
3 years ago
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