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sveticcg [70]
2 years ago
10

You stretch your arm and rotate around the center of yourself in the horizontal plane. Suppose you make 2 full revolutions every

1 second, and the distance from the center of your body to the tip of your finger is 1.2 m.
Find:
(a) Find the angular speed of your rotation
(b) Find the period of rotation.
(c) Find the speed of the tip of your finger

Physics
1 answer:
lakkis [162]2 years ago
8 0

(a) The angular speed of the rotation is 12.57 rad/s

(b) The period of the rotation is 0.5 s.

(c) The speed of the tip of your finger is 15.08 m/s.

<h3>Angular speed of the rotation</h3>

The angular speed of the rotation is calculated as follows;

ω = 2πN

where;

  • N is number of revolutions

ω = 2π x (2) = 4π  = 12.57 rad/s

<h3>Period of rotation</h3>

\omega = 2\pi f\\\\f = \frac{\omega}{2\pi} \\\\T = \frac{1}{f} = \frac{2\pi}{\omega} \\\\T = \frac{2\pi}{4\pi} = 0.5 \ s

<h3>Speed of your finger</h3>

v = ωr

v = 12.57 x 1.2

v = 15.08 m/s

Learn more about angular speed here: brainly.com/question/6860269

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Answer:

2.55sec

Explanation:

time = distance/speed = (87 m)/(34 m/s) = 2.55sec

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In the formula vy = ayt, what is the value of ay for an object in projectile motion?
Sergeu [11.5K]
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3 years ago
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Reptile [31]

Answer:

v (speed) = S / t = 4 * 400 m / (6 * 60 sec) = 4.4 m/s

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Which of the following is a scalar quantity?
schepotkina [342]

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B. Time

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5 0
3 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 41m in front of you. Your reaction time
nordsb [41]

Answer:

Maximum speed you could have and still not hit the deer = 24.07 m/s

Explanation:

Let the maximum speed you could have and still not hit the deer be y.

Your reaction time before stepping on the brakes is 0.50s.

Distance traveled during this time = 0.5y

A deer steps onto the road 41m in front of you

Remaining distance to deer = 41 - 0.5y

The maximum deceleration of your car is 10 m/s²

We have equation of motion, v² = u² + 2as

       Initial velocity, u = y m/s

       Final velocity, v = 0 m/s

       Acceleration, a = -10 m/s²

       Displacement, s = 41 - 0.5y

Substituting,

       v² = u² + 2as

        0² = y² + 2 x -10 x (41 - 0.5y)

          20(41 - 0.5y) = y²

           820 - 10 y = y²

            y² + 10 y -820 = 0

             y = 24.07 m/s or y = -34.06 m/s(not possible)

Maximum speed you could have and still not hit the deer = 24.07 m/s

           

7 0
3 years ago
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