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sveticcg [70]
2 years ago
10

You stretch your arm and rotate around the center of yourself in the horizontal plane. Suppose you make 2 full revolutions every

1 second, and the distance from the center of your body to the tip of your finger is 1.2 m.
Find:
(a) Find the angular speed of your rotation
(b) Find the period of rotation.
(c) Find the speed of the tip of your finger

Physics
1 answer:
lakkis [162]2 years ago
8 0

(a) The angular speed of the rotation is 12.57 rad/s

(b) The period of the rotation is 0.5 s.

(c) The speed of the tip of your finger is 15.08 m/s.

<h3>Angular speed of the rotation</h3>

The angular speed of the rotation is calculated as follows;

ω = 2πN

where;

  • N is number of revolutions

ω = 2π x (2) = 4π  = 12.57 rad/s

<h3>Period of rotation</h3>

\omega = 2\pi f\\\\f = \frac{\omega}{2\pi} \\\\T = \frac{1}{f} = \frac{2\pi}{\omega} \\\\T = \frac{2\pi}{4\pi} = 0.5 \ s

<h3>Speed of your finger</h3>

v = ωr

v = 12.57 x 1.2

v = 15.08 m/s

Learn more about angular speed here: brainly.com/question/6860269

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Answer:

a) The car was moving at a speed of 29.167\ m.s^{-1}

b) The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c) f_o=1283.33\ Hz

Explanation:

Given:

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  • speed of the source, v_s=0\ m.s^{-1}
  • velocity of the obstacle car be, v_o
  • speed of sound, s=350\ m.s^{-1}
  • observed frequency, f_o=1100\ Hz

<u>Using the equation from the Doppler's effect:</u>

\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}

\frac{1100}{1200} =\frac{(350+v_o)}{350-0}

v_o=-29.167\ m.s^{-1}

a)

The car was moving at a speed of 29.167\ m.s^{-1}

b)

The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c)

Now when, v_s=50\ m.s^{-1}

Then, f_o=?

Using the Doppler's eq.:

\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}

f_o=1283.33\ Hz

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What is the Ultraviolet Catastrophe?​
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Closed circuit
VMariaS [17]

A. the light bulb goes out once the circuit is open since it causes the flow of electricity to cut off. the light bulb dosent get the energy it needs to light up

Explanation:

B. a simple example of this in our every day life is a light switch. when you switch the light on then the circuit is closed and the energy transfers to the light bulb, when u switch the light off then you cut off the lights source of energy which causes the light to turn off.

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harkovskaia [24]

Answer: a) io=233.28 A ( initial current); b) τ=R*C= 22.31 ms; c) 81.7 ms

Explanation:  In order to explain this problem we have to use, the formule for the variation of the current in a RC circuit:

I(t)=io*Exp(-t/τ)

and also we consider that io=V/R=(1.5/6.43*10^3)

=233.28 A

then the time constant for the RC circuit is τ=R*C=6.43*10^3*3.47*10^-6

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I(t)=io*Exp(-t/τ)  for I(t)/io=0.0257=Exp(-t/τ) then

ln(0.0257)*τ =-t

t=-ln(0.0257)*τ=81.68 ms

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