Question

You stretch your arm and rotate around the center of yourself in the horizontal plane. Suppose you make 2 full revolutions every 1 second, and the distance from the center of your body to the tip of your finger is 1.2 m.
Find:
(a) Find the angular speed of your rotation
(b) Find the period of rotation.
(c) Find the speed of the tip of your finger

Answer 1

(a) The angular speed of the rotation is 12.57 rad/s

(b) The period of the rotation is 0.5 s.

(c) The speed of the tip of your finger is 15.08 m/s.

Angular speed of the rotation

The angular speed of the rotation is calculated as follows;

ω = 2πN

where;

• N is number of revolutions

ω = 2π x (2) = 4π  = 12.57 rad/s

Period of rotation

$\omega = 2\pi f\\\\f = \frac{\omega}{2\pi} \\\\T = \frac{1}{f} = \frac{2\pi}{\omega} \\\\T = \frac{2\pi}{4\pi} = 0.5 \ s$

Speed of your finger

v = ωr

v = 12.57 x 1.2

v = 15.08 m/s

Learn more about angular speed here: brainly.com/question/6860269